Recent content by a lone fishy

what would B and C affect? Does it only affect how far down the river you go?

Homework Statement [/B] To cross a river with a current (flowing downstream) in the least amount of time, a boat should point a) directly at the opposite shore b) somewhat upstream c) somewhat downstream d) in a direction that will take the boat directly across e) downstreamHomework...

well if i think about a car on the highway, when we accelerate even more, our body moves slams backward in the seat before our bodies adapt to the change in velocity. But now that I think about it, I'm not quite sure where the marble would move left then right

thank you

How about the second option that I've written? In both cases the person can be seen moving to the west even when the train moves to the east. Is one answer more right than the other?

So that would mean reducing the train's speed to 12 m/s i assume

Definetely

their relative velocties would be the same i believe so the question I have now is that to just avoid collision, if the train reduces its speed to the same as the freight train, they would never collide correct? But then again if the train reduces its speed to zero then they would never collide...

I believe so. Your wording is a bit confusing :s

Homework Statement An observer on the ground sees a person on a train just leaving the station in the east direction. explain how the observer on the ground could see the person moving to the west while the train is moving east Homework EquationsThe Attempt at a Solution At first I thought...

Homework Statement The driver of an express train traveling at 38 m/3 [E] sees a freight train 120 m ahead on the same line traveling at a constant velocity of 12 m/2 [E]. He immediately applies his brakes and just avoids a collision. Assume that the freight train maintains its constant...

Ah I think i got it now. Right now we have the following: 1.8=(86.8+d)/(28+t). If we find that d then we can have an equation solvable for t. In interval two we have 1.3 = distance / t and this equals to: distance = 1.3t Then we can plug in that value as the d and solve for t :D

I didn't quite understand your second line. Right now I have 1.8=86.8 + d / 28 + t where 1.8 is the average speed of the whole trip, d is the unknown distance from the second interval, and t is the unknown time from the second interval. Im not sure if I am on the right track nor where to...

Homework Statement A golfer rides in a golf cart at an average speed of 3.1 m/s for 28s. She then gets out of the cart and starts walking at an average speed of 1.3 m/s. For how long must she walk if her average speed for the entire trip, riding and walking, is 1.8 m/s ? Homework Equations...

nevermind i got it solved now. thx