Recent content by A M

Yes you're right, but to be honest, I've already given up writing that article. Anyway, thanks for your correction! :smile:

-Please close this thread-

Even for beginners?

I hope you don't mind me asking, but could you be a bit more explicit?

Do you really mean I should write something new? I'm not a scientist...

What if I show the diagrams of each term and then combine them together? E.g. for the shape of energy due to strong nuclear force I can say this force has short range characteristics and thus for lightest nuclei the energy due to the strong force grows rapidly. But this trend approaches a limit...

The reverse; an unclear explanation that's correct is not preferable to me! I'm not. If you see my first posts, you'll understand that I accepted my mistakes, improved my understanding, and edited my article. If you consider the post#20, you'll know that I worked hard to improve my...

Just think a 'beginner' with "admitted level of knowledge" wants to read this from Wikipedia. At first it says ##Q=Ze##; so ##E## 'equals' ##(Ze)^2/(r_0 A^{1/3})##. But because ##Z^2≈Z(Z-1)##, ##E## is 'almost equal to' ##3e^2{Z(Z-1)}/20πε_0r_0 A^{1/3}##. Doesn't it really mean that ##Z(Z-1)##...

By this statement, I just meant that my understanding of this force is in contrast with what has been said, and thus it is getting 'more and more confusing to me'. I did not mean that "their contributions" are getting worse. I'm not a native or a good English speaker. I sometimes can't express...

Yes, I know, but I think the explanation of most online sources isn't correct; For example I've seen Wikipedia, washington.edu, and Lecture 19. In washington and lecture, it's written that the dependence is on ##Z^2##. And also the way ##Z(Z-1)## is explained in wiki and lecture, can be by...

But I don't agree. As I said we can consider the Coulomb energy of hydrogen as zero, and then use ##Z^2## for other nuclides. As written in Wikipedia & int.washington.edu , a more reliable version is ##Z^2##, but since ##Z^2≈Z(Z-1)## and it goes to zero for hydrogen, we use ##Z(Z-1)##.

I've just decided to remove that formula; because the Liquid Drop Model & SEMF provide a poor (and even wrong) fit for lightest nuclei. And also as you said, if I mention this formula in an introduction article, I should give a motivation and thus a lot of text would be added. SEMF: Coulomb...

The article I want to publish in PF 'insights blog'. I'm told to share my basic understanding first and ask if they're correct. The post #10 is a small part of that article.

Yes, answering questions is useful, but a thorough understanding of 'fundamental' definitions is a better choice. (For example if you knew what exactly a radioactive decay is, or how to calculate released/utilized energy in nuclear reactions, you would understand this part better.) Well, the...

I'm glad to hear it! This is exactly the question written in my article. I know you won't wait until my article gets published, so I send you the related part: Thus, electric forces do not hold nuclei together, because they act in the opposite direction. What exactly confines these positively...