I made a mistake with the first equations it is P=pot diff²/R => R= pot diff²/R so I ended up recalculating and I got 6.384x10^4 but it is still not right.
A person runs a 9.0 V, 12.0 W radio for 1.33 hours. How many coulombs of charge pass through the wires in the radio during this time?
I used Power= pot difference/Resistance = 9v/120w=7.5e-2
I=current
Then I used I²=P/R= 120v/7.5e-2 = 1.6e3
I=40A
1.33h*60mins*60secs = 4.788e3...
A proton is released from rest and accelerates through a potential difference V. The final speed of the proton is proportional to the potential difference in which of the following ways?
A. V
B. V^1/2
C. V^-1/2
D. V^-1
I think it is V^(1/2) (just√V) but I am no sure exactly how to find...
I'm review for a test in the morning and just making sure I have this right. The professor did not include a key for the review.
ere is a link to the image for both problems.
In the figure, two curved plastic rods form a circle of radius R in the standard x-y plane.
The charges of the...
In the figure shown, electrons 1 and 2 are on the x-axis while charges
3 and 4 are on the y-axis. The charges 3 and 4 are identical with
charge -Ne and at identical angle θ(theta). N is an integer. Electron 2 is
free to move while the other charges are fixed in place a horizontal
distance R...
Derive your results algebraically… No graphical results.
An excess charge of +Q is distributed into two unequal parts, one having charge +q .
Assume that these two new charges are now separated by a non-zero distance. What value of q maximizes the repulsive electric force that one of these new...
This is a problem from Web Assign which is a web site you are assigned homework through. I'm wondering if there is an error and both charges should have been positive.
Two small spheres, each of mass 4.00 g, are suspended by light strings 10.0 cm in length. A uniform electric field is applied in the x direction. The spheres have charges equal to -2.00 multiplied by 10^-8 C and +2.00 multiplied by 10^-8 C. Determine the electric field that enables the spheres...
A proton orbits just at the surface of a charged sphere of radius 0.83 cm. If the speed of the proton is 4.96 X105 m/s, what is the charge on the sphere?
proton mass = 1.67e-27
proton charge = 1.6e-19
Radius = .0083 meters
I thought maybe F = (mv²)/r
((1.67e-27)(4.96e5)²)/.0083...