Recent content by ab94

  1. A

    What Is the Change in Entropy for Condensing and Freezing 45g of H2O?

    I think I solved my mistake, I'm not supposed to divide by T at the end, I need to do it for each step. So q1= -101610J/373.15K = -272.3J/K q2= 45gx4.2J/K/g x ln(273.15K/373.15K) = -58.96J/K q3= -15030J/273.15K = -55.02J/K Total Change in Entropy= -386.3J/K
  2. A

    What Is the Change in Entropy for Condensing and Freezing 45g of H2O?

    Homework Statement 45g of H2O(g) are condensed at 100 degrees C, and H2O(l) is cooled to 0 degrees C and then frozen to H2O solid. Find the Change in Entropy H2O(l): 4.2 J K-1g-1 vaporization at 100 degrees C: 2258 J g-1; fusion at 0 degrees C: 334 J g Homework Equations dS=dq/TThe...
  3. A

    Biology Punnet Square Question

    Homework Statement The Xolo is the national dog of Mexico. The striking characteristic of this dog is that it has no hair. Xolos carry a mutation in Chromosome 17 that, when homozygous, is lethal. If two hairless Xolos were mated, what fraction of their surviving offspring would be...
  4. A

    How Does Doubling Internal Energy Affect Pressure in a Sealed Container?

    Homework Statement For example in the problem if we have a volume of 10L at 15 degrees Celsius, and there is initially 100Pascals pressure, what would the final pressure be if we double the Internal Energy? Homework Equations U=3/2nRT The Attempt at a Solution I though pressure was...
  5. A

    How to find the derivative of this?

    Nvm I got the right answer, I used wolframalpha and I subtracted my answer from theirs, and got 0. (i fixed my own error up there ^) Thanks for the help
  6. A

    How to find the derivative of this?

    Ok so: ln(y)= ln(p^x^p) + ln(x^p) ln(y)=(x^p)ln(p) + (p)ln(x) 1/y y'= (px^(p-1))ln(p) + (x^p)/p + 0 + p/x therfore y'= p^x^p(x^p)(px^(p-1))ln(p) + (x^p)/p + + p/x Is this correct? or is there an error
  7. A

    How to find the derivative of this?

    Ohh thanks, I was taking the highest exponent (p) instead of the entire exponent (xp). I'll post my solution after I work it out
  8. A

    How to find the derivative of this?

    so then would I split up the ln's into ln(y)=ln(p^x^p) + ln(x^p) ? If so I ended with y' = p^x^p(x^p) (plogp + p/x) ...don't think that's right
  9. A

    How to find the derivative of this?

    Yes, that's what it is. So I can't take ln of both sides and say ln(y)=ln(p^x^p) ln(y)= pln(p^x) ? I thought We could bring down exponents when using that ln property.
  10. A

    How to find the derivative of this?

    Homework Statement Find dy/dx of this: Assume p>0, y=(p^(x^p))(x^p) Homework Equations 1. d/dx f(x)g(x)h(x) = f'(x)g(x)h(x)+f(x)g'(x)h(x)+f(x)g(x)h'(x) The Attempt at a Solution ln(y)= p(ln(p^x))x^p 1/y y'=p'(ln(p^x))x^p + p(logp)x^p + p(ln(p^x))px^(p-1) --use "revlevent"...
Back
Top