Recent content by Accurim

Homework Statement The problem - Consider lines L1 and L2: L1: r1 = (X,Y) = (1,2) + T (6,1) L2: r2 = (X,Y) = (1,2) + K (4,3) Find an equation for either of the bisectors of the angles between L1 and L2Homework Equations The Attempt at a Solution cos\alpha =...

Homework Statement Okay this isn't really a question from the textbook or anything but I'm having a horribly hard time trying to find information on an experiment involving c14, paramecia and alcohol. There are questions I have to answer about this and I've tried googling for information for...

Ah I missed that integer sign on the 3. Anyways I went with the answer I got before so thanks for the help guys.

For k=-1/5 and k=3 a\bullet b = |a||b|cos\alpha (2,3,-1)\bullet(-1, K, 1) = (\sqrt{2^2+3^+{-1}^2})(\sqrt{k^2+(-1)^2+1^2})(\frac{3}{7}) -2 +3k -1 = \sqrt 14\sqrt{k^2+2}(\frac {3}{7}) 3k-3=\sqrt14 \sqrt {k^2+2}(\frac {3}{7}) 7k-7=\sqrt 14\sqrt {k^2+2} 7(k-1)=\sqrt 14\sqrt {k^2+2}...

I actually squared both sides and depending on when you square both sides you'll get different answers. I got 4 answers depending on when I square both sides. I tested the values of K and only 1 out of 4 them are correct, I'll show you what I did. a\bullet b = |a||b|cos\alpha...

Hi I'm new here and I'm having trouble with this algebra question please help. Sorry if my latex is ugly I'm new to it. I get stuck at the bottom line and I'm not sure how to go further with the question to solve for K #7 - Angle between 2 vectors is \alpha where cos\alpha = \frac{3}{7}. a =...