Recent content by Acookook

Hi! Sorry, for the late reply, but I had other thing to do. :woot: I asked my teacher for the explanation, but he told me that I have everything to solve the problem. I talked to my classmates and they've we have written these formulas posted above, related it to the problem with the spring...

I will ask my teacher what he meant with the 0.2s^-1 and post a clarified answer tommorow.

On the cube the force is acting is 5N and is extended by 50mm So the constant according to hook's law is F=kx => 5N/0,05m =100. The time absortion coefitient of the swing is 0.2 s ^-1. It also bothers me too, because In my school book the is no real refence. For the circular freq I have...

The cube itself is 1kg =10N, we tow it with 5N (so 15N in total). I misscalculated 120, but in general I can use hooks law to calculate the k=F/s (50milimeters). The absortion coffetient determines how much sound is absorbed. If the abs. koef = 1, then no sound is reflected.

Hi! I am Alex and I just joined this forum. I am very awful at physics (at least) at undestanding the subject. When given a proper explanation I understand it and can solve anything I desire. But not everything is so easy as it seems.

Am I trying to solve a simple equation, but get stuck at the basic. I have have a spring with a cube attached to it (1kg). When I pull it with 5N, the spring extends to 50mm =amplitude, (Hooks law) the koefitient is 120. The determined absortion coeffitient is 0,2^-1s. I tried to get the...