Recent content by ACSC

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    Interpreting and converting an acceleration-time graph

    Oh... I see now. It doesn't slow down to 15m/s but slows down 15m/s. So like this, right?
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    Δt and Limit of Δx/Δt as Δt -> 0 at t=3?

    Can we assumed that ti=0 and tf=3? Though that would be the exact same thing as t=3, wouldn't it? I'll email my teacher and ask what they want the form of the answer to be. GREAT! Thank you so much for guiding me. :)
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    Interpreting and converting an acceleration-time graph

    Homework Statement Homework Equations a = Δv/Δt v = Δx/Δt x = area under velocity graph The Attempt at a Solution According to my second attempt, the answer to "particle's speed at t = 20.0 s?" is not 15m/s either. Working out picture. I don't understand where I went wrong. I've always...
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    Δt and Limit of Δx/Δt as Δt -> 0 at t=3?

    Oh, I forgot to times the 5 into the last part. Thanks. xf = 5Δt2 + 30Δt + 45 ? The question wants the answer in meters though. :S If I sub in Δt=3, I would get 180m. Would that be it? Seems like there's something wrong in subbing Δt=3, though. I think I get what you mean. Like this?
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    Δt and Limit of Δx/Δt as Δt -> 0 at t=3?

    I think that makes sense, thank you. Would (b) be 144m? Is the second working out for (c) correct? Working out picture here.
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    Δt and Limit of Δx/Δt as Δt -> 0 at t=3?

    I'm still not quite sure what to do. Do I make the t in the x equation the subject the simultaneously solve it? Isn't (b) asking for the distance traveled rather than Δt? This feels like a really simple question that I'm supposed to understand straightaway. I've done basic physics and that...
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    Δt and Limit of Δx/Δt as Δt -> 0 at t=3?

    1. Homework Statement The position of a particle moving along the x-axis varies in time according to the expression x = 5t^2, where x is in meters and t is in seconds. Evaluate its position at the following times. (a) t = 3.00 s x = ? m (b) t = 3.00 s + Δt xf(final x) = ? m (c) Evaluate...
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