I said that solution was
E[X] = Integral From 0 To 2 [ 2*f(t)dt ] + Integral From 2 To Infinity [ t*f(t)dt ]
Which is almost the same as you posted
It should be:
E[X] = 2 [1-Exp[-2/3]] + Integral From 2 To Infinity [ t*f(t)dt ]
Best Regards
Hello, Thank you for replying
The problem in this case is that the constant random variable is involved in an order statistic, so it is not so trivial to see the sample space of each of the random variables
I did this: Write the random variable X as:
X = 2 I(0,2](T) + T I(2,Infinity)(T)...
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