Recent content by actcs

I said that solution was E[X] = Integral From 0 To 2 [ 2*f(t)dt ] + Integral From 2 To Infinity [ t*f(t)dt ] Which is almost the same as you posted It should be: E[X] = 2 [1-Exp[-2/3]] + Integral From 2 To Infinity [ t*f(t)dt ] Best Regards

Hello, Thank you for replying The problem in this case is that the constant random variable is involved in an order statistic, so it is not so trivial to see the sample space of each of the random variables I did this: Write the random variable X as: X = 2 I(0,2](T) + T I(2,Infinity)(T)...

Good Evening: I'm given this problem: A device that continuously measures and records seismic activity is placed in a remote region. The time, T, to failure of this device is exponentially distributed with mean 3 years. Since the device will not be monitored during its first two years of...

Well, you're completely right about the total number of possible random walks, I must have miscalculated. On the other hand, to calculate the probability it isn't just as simple as dividing by 1024 once we have worked out the number of random walks which stay in the inner 3x3 grid, that's...

A grid of 4x4 is given .__.__.__.__. | | | | | .__.__.__.__. | | | | | .__.__o__.__. | | | | | .__.__.__.__. | | | | | .__.__.__.__. A ball is located at the center of the grid which is to perform a 5 step random walk with equal probability in any...