Positive charge Q is distributed uniformly along the x-axis from x=0 to x=a. A positive point charge q is located on the positive x-axis at x=a+r, a distance r to the right of the end of Q.
Problem:
Calculate the x-component of the electric field produced by the charge distribution Q at...
I have 2 questions which I'm just pondering because I can't answer them
First is
If triamminetetrachloroplatinum(V) ion (Pt(NH3)2Cl4 +) were to be put into a hexagonal planar geometry, how many geometric isomers would it have? Is it possible to have this arrangement or not from what you...
Maybe you should read up on it a little. The hints they give you are pretty helpful.
Think about calculating torque around a point that will yield a simple equation and then use a couple of those equations to get an expression for Q.
A box is separated by a partition into two parts of equal volume. The left side of the box contains 500 molecules of nitrogen gas; the right side contains 100 molecules of oxygen gas. The two gases are at the same temperature. The partition is punctured, and equilibrium is eventually attained...
OH! MY! I get it! I've been trying to do it with a lot of math all this time, but now I realize the answer. Thanks whozum and especially you OlderDan!
So the first book would hang off .5L, the second would hang off .75L, the third .875L... yeah!
Well, that's my problem, I don't know how to apply the equilibrium torque concept to get the total length :cry: . Once I think about the two books on top of each other, I don't even know where to start for values of L.
If you put a uniform block at the edge of a table, the center of the block must be over the table for the block not to fall off.
If you stack two identical blocks at the table edge, the center of the top block must be over the bottom block, and the center of gravity of the two blocks...
SHM with torque? Springs and frequency mass relation?
Problem 1
A slender, uniform, metal rod with mass M is pivoted without friction about an axis through its midpoint and perpendicular to the rod. A horizontal spring with force constant k is attached to the lower end of the rod, with the...
Doc Al was right. (though maybe your way Nenad could also produce the "correct" answer)
T - mg = -ma because acceleration is downward.
2T = mg
T = (mg)/2
Darn little technicalities.
Thanks guys! You helped me finish my homework on time :biggrin: .
A string is wrapped several times around the rim of a small hoop with radius r and mass m. The free end of the string is held in place and the hoop is released from rest.. (picture attached~)
So I tried using moment of inertia as mass*radius^2, so torque would be MR^2*alpha, and it would also...