Recent content by addmeup

ok yeah i think i got it, so now I'm at e^-θ - sin(2θ) - ∫1/2sin(2θ) * e^-θ what do i do with the ∫1/2sin(2θ) * e^-θ? Take the anti derivative right? would that be -(1/2)cos(2θ) * e^-θ?

This is probably a stupid question but why would it be?

i got du= e^-theta and v= sin(2theta)

Homework Statement Evaluate the integral (e^-theta) cos(2theta) I got this as my answer e^(-theta)-sin(2theta)+cos(2theta)e^(-theta)+C But it was wrong All help is appreciated.