Recent content by addy899

the potential from the other planet is the same... so the potential at the midpoint is 2MmG/5R?

Halfway between the center of the two planets is 5R, so the potential E from the second planet at half way is MmG/5R Conceptually, the potential at that point is 0 because the planets pull on it equally?

What we need to find is the amount of energy to get the rocket half way to the other planet, right? this can be found y finding the difference between the potential energies at the surface and half way through? Potential at the surface is MmG/R - MmG/9R = 8MmG/9R The second term is the...

1. Description of Problem A binary planet system comprises two identical planets of mass M and radius R with their centers a distance 10 R apart. The minimum energy that the engines of a spacecraft need to supply to get a rocket of mass m from the surface of one planet to the surface of the...

θ=36.9° ok, since we already know the length of the sides, we get 3.6 = 5 - 5cos(36.9)μk 5 is the force from gravity parallel to the slide 5cosθ is the normal force perpendicular to the slide this gives me μk=.35

Δh = .153m, PE=3J using KE, v=1.732m/s so Fcp=6N so now I have to break this into its horizontal component: Fx=6sin37=3.61 I JUST REALIZED I MISCLACULATED ABOVE mgsin(37)=11.8 add this to the tangential force of 11.8N = 15.4N and I get 7.7m/s2 I'm confused. The coordinate...

Homework Statement A child's slide is flat, 5 meters long, and sloped down so that the top is 3 meters higher than the bottom. A child slides down, starting from rest, and has v = 6 m/s at the bottom. Find the coefficient of kinetic friction, μk is: Homework Equations F=ma f=μkFN...

T is parallel to mgcosθ so the net force on the pendulum is mgsinθ=15.6N using f=ma, a=7.83m/s2 Is this correct? The answer key I have says the acceleration is 7.2m/s2

Homework Statement A 2 kg mass hangs from the end of a 1 meter long string which is Øxed at its other end. The mass is displaced so that the string is at 53° to the vertical and released (remember sin(53°) = cos(37°)=0.8). Find the magnitude of the total acceleration of the mass when the...

forgot to divide by 2... goodness. Thanks!

1. Two carts, each of mass M, travel towards each other on a frictionless air track, one with velocity V, and the other with -3V. They collide and stick together. How much kinetic energy is lost in the collision? 2. P = mv, KE=1/2mv2 3. Initial KE of the system is the sum of the kinetic...