Recent content by adelaide87
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Electric flux through the surface of half a sphere?
Homework Statement Electric Field is given by E=(100i-200j+100k) N/C. What is the electric flux through the surface of half a sphere? (The surface is a hollow bowl open upwards, positive in the z direction, radius of 2). Homework Equations The Attempt at a Solution Ive...- adelaide87
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- Electric Electric flux Flux Sphere Surface
- Replies: 1
- Forum: Introductory Physics Homework Help
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Help with setting up Integrals for volumes
are a and b correct though?- adelaide87
- Post #3
- Forum: Calculus and Beyond Homework Help
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Help with setting up Integrals for volumes
Homework Statement Hi I am trying to find the volume of a shape.I don't need help to solve, but I would like a hand setting these integrals up. I've only recently started doing volumes, so bear with me. Using the curves: y=x x=2-y^2 y=0 Indicate the method used and set the...- adelaide87
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- Integrals Volumes
- Replies: 4
- Forum: Calculus and Beyond Homework Help
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Calculating the Centroid of x=2-(y^2) and the Y Axis
Homework Statement Easy question: Find the centroid of x=2-(y^2) and the y axis Homework Equations The Attempt at a Solution Already calculated, I got an area of (4/3)(√2) Cx = 4/5 Cy = 0 When calculating Cx, in the book they have: Integral (x)(√(2-x)) And go...- adelaide87
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- Axis Centroid
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Why is this limit not well defined?
For -1 < (3 - x)/(x + 4) < 1. Should the signs be less than/equal to?- adelaide87
- Post #15
- Forum: Calculus and Beyond Homework Help
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Why is this limit not well defined?
Would it be correct to say it's not well defined because f(x) is not defined for x < -4? Because (3 - x)/(x + 4) -> -1 as x -> -infinity, its approaching from values that are less than -1. arccos[(3 - x)/(x + 4)] is only defined when -1 < (3 - x)/(x + 4) < 1. Does that seem correct?- adelaide87
- Post #13
- Forum: Calculus and Beyond Homework Help
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Why is this limit not well defined?
Ah wait a sec, anything greater than x=1 is undefined. But you don't have to even worry about anything greater than 1, because its x > -infinity. Thats why i don't see how it is undefined.- adelaide87
- Post #11
- Forum: Calculus and Beyond Homework Help
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Why is this limit not well defined?
So is it that inverse cosine that makes it not well defined? Because as you plug -ive x values in it goes to -infinity. Correct?- adelaide87
- Post #9
- Forum: Calculus and Beyond Homework Help
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Why is this limit not well defined?
Im confused. I have never done a question like this one and it randomly asked it.- adelaide87
- Post #6
- Forum: Calculus and Beyond Homework Help
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Why is this limit not well defined?
Left. Does it help to put the cos on the bottom?- adelaide87
- Post #3
- Forum: Calculus and Beyond Homework Help
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Why is this limit not well defined?
Lim x--> -Infinity cos^-1[(3-x)/(x+4)] Book says this limit is not well defined, why is that?- adelaide87
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- Limit
- Replies: 16
- Forum: Calculus and Beyond Homework Help
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How do you go from (3w-1)/(w+2) and get: 3-(7/(w+2))?
This one is a bit trickier 1/[(u^2)(u-1)(u+1)] to get (1/2)/(u-1) - 1/(u^2) - (1/2)/(u+1) I tried doing it they way you just showed me but I get stuck.- adelaide87
- Post #6
- Forum: Calculus and Beyond Homework Help
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How do you go from (3w-1)/(w+2) and get: 3-(7/(w+2))?
What about this one? 2x/((x+3)(x+1)) Simplified to 3/(x+3) - 1/(x+1) This is probably one of the harder parts of algebra for me for some reason. I don't understand the steps.- adelaide87
- Post #4
- Forum: Calculus and Beyond Homework Help
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How do you go from (3w-1)/(w+2) and get: 3-(7/(w+2))?
How do you go from (3w-1)/(w+2) and get: 3-(7/(w+2))?- adelaide87
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- Replies: 6
- Forum: Calculus and Beyond Homework Help
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How to Integrate Cotangent and Cosecant with Odd Powers?
Describe the method you would use to integrate cot^a(x) csc^b(x) dx If a and b are odd? An explanation of the strategy would be a huge help!- adelaide87
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- Integrate
- Replies: 2
- Forum: Calculus and Beyond Homework Help