Recent content by adi adi

first i derive my y=√(a2-x2) into y'= - x/√(a2-x2) and then put it into arc length equation = ∫ √(1+(dy/dx)2) dx resulting ∫ √(1+(- x/√(a2-x2))2) dx and i got stuck there. i don't know how to solve my equation, and i didnt use trigonometric substitution

yeah, i make the circle equation into y= √(a2-x2) , and then put it into the arc length equation. the problem is i can't solve my integral equation.

Homework Statement find the arc length of a circle in the first quadrant with an equation x2 + y2 = a2 Homework Equations arc length = ∫ √(1 + (dy/dx)2) dx The Attempt at a Solution i got stuck on how to solve the integral

so to make clear things the ratio of atomic radius is same but the nuclear radius isn't same right?

so i get this : A (sin100tcosΦ + sinΦcos100t) when 100t=0, i get this : A sin Φ when 100t=pi/w, i get this : A cos Φ so how do i find the Φ ? thank you for being patient because I am veeery slow at trigs.

Homework Statement so my friend asked this question: "what's the atomic radius ratio between He-3 and He-4?" 2. Homework Equations all i know is this equation : r =nh/mv 3. The Attempt at a Solution i thought the ratio will be same because both He-3 and He-4 have only two electrons. Correct...

yeah thank you, so how do you solve this case? i change the second wave function (Z2) from 6sin(100t-pi/2) to -6cos(100t), so i have this problem : 8sin(100t) - 6cos(100t), and i got stuck right there.

sorry can you submit your work here? i got stuck

sorry i mean sin(-x) = -sin(x)

sorry isn't sin -(x) = - sin x ?

pardon me i don't understand where does the cos come from?

Homework Statement so there is this problem : find the amplitude from the superposition of Z1 and Z2 where Z1 : 8 sin 100t, A1= 8m and Z2 : 6 sin (100t-pi/2), A2=6m Homework Equations i know that all we need to do is add them and do the trig using sine additon, but i couldn't do that because...

thank you so much. this really helpful

so i can still use Deviation angle = i1+r2-beta to find second refraction angle? (r2) thank you so much that enlightens me so much about prism. many thanks man

if i solve this equation to find first refraction angle (r1) : sin(I1) = np sin (r1), which (I1) is incident angle =60 degree, and np is prism refraction index = 1,6 i find r1 = 32,76 degree. if beta = r1 + I2 , which beta is apex angle = 30 degree, and I2 is second incident angle, i find I2 =...