Recent content by ae4jm

Homework Statement Car Dynamics f(t)→ \frac{\frac{1}{M}}{s+\frac{D}{M}}→y(t) Applied Force Velocity Homework Equations M=1,000 kg and D=1000 kg/s Where f(t) represents the input force and y(t) is the output velocity. M is the Mass and D...

Okay, for the grand finale: I1=30.71∠-47.49° A I2=30.71∠169.38° A Thanks a ton for all of your help and for not letting me drown out in the open ocean, LOL. I can see that I would have gotten the incorrect answer anyways even if my equations were correct to begin with. I had errors in...

After changing that induced value in the primary I have: (1+j4)I1+j2I2=100 and J2I1+(-1.2+j2.4)I2=0 Thanks again for all of the work that you have put into helping me.

Is the correct answer: I1=37.21ang-82.875 deg A I2=27.735ang-70.56 deg A Look correct?

I initially have 100-1I1-j4I1+j2I2=0 and then I consolidate and move everything on one side except for the 100 and solve simultaneously...should I rearrange my equation?

(1+j4)I1-j2I2=100 In the Primary j2I1+(-1.2+j2.4)I2=0 In the Secondary

Okay, I got I1=24.5∠-75.96° I2=0.5∠-90° I double checked what I had with dot notation. I would have +M for the primary because my current goes into j2 in the secondary at the dot, and goes from + to - for a voltage drop across the inductor j4 for itself voltage drop. Then for the...

Ok, thanks. I'm going to grab some dinner and then I'm coming back to work on this some, as well as cover everything else for this course' final. Thanks a lot, I played around with the transformer equations a little, letting everything in the secondary equal ZL, minus the inductor equations...

Thanks for your help. Okay, so combining the loops I2 and I3 I have the 2Ω resistor and -j2Ω in series and then in parallel with the 2Ω resistor which totals (1.2-j0.4)Ω in place of the original 2Ω resistor and now that give me the following mesh equations to solve: For I1: I1(1+j4)-j2I2=100...

When I apply the equations in phasor domain V1=jω(L1)(I1)±jωM(I2) and V2=jω(L2)(I2)±jωM(I1) and then mesh analysis should I consider the other mesh on the far right side with the capacitor? In other words, this is the first problem that I've seen or had such as this and since I2 is a...

Thanks Pilgrimman. You are correct; this is how the professor demonstrated the solution to the problem on the board. He used KCL, showing the 6A and 4A in was 10A out. Ix was equal to 10A and then this 10A multiplied by the 1.5 gave the 15volts. Then he skipped straight to 20(6)=120watts...

According to the professor, he says that the correct answer is 120watt; does anyone else get 120watt? Where did I go wrong in my solving?

Thanks Pligrimman, So with Kirchoff's current law (4+6) gives me Ix=10. Then 1.5Ix=15V. The potential difference in voltage is 15V-5V=10V across B. Then, since the current across B is 6A and the voltage is 10V, I would have 60W absorbed by B? Does this sound correct? I got a little...

Find total Power absorbed or delivered to Element "B". I'm supposed to find how much power was absorbed or delivered by element "B". What is the thought process/solving technique for this type of problem? This was a quiz problem, it has already came and gone; if I see a problem like this...

Please, can you guys offer me any guidance? After I find the derivative and plug it into the original DE and I solve the solution for y and plug it into the original DE I'm not getting the solution to be correct.