Recent content by aicort
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Extreme values (Lagrange multipliers)
is it correct? http://img245.imageshack.us/img245/4636/lagrange.th.jpg- aicort
- Post #5
- Forum: Calculus and Beyond Homework Help
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Extreme values (Lagrange multipliers)
no, in fact g(x,y)=4x^2{}+9y^2{}=36 but well, I wrote it that way because is the way my book does- aicort
- Post #3
- Forum: Calculus and Beyond Homework Help
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Volume of a solid limited by two paraboloids
you say so? I'm glad then... i thought it was wrong thanks you guys :)- aicort
- Post #6
- Forum: Precalculus Mathematics Homework Help
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Extreme values (Lagrange multipliers)
determine, if any, the maximum and minimum values of the scalar field f (x, y) = xy subject to the constraint 4x^2{}+9y^2{}=36 The attempt at a solution using Lagrange multipliers, we solve the equations \nablaf=\lambda\nablag ,which can be written as f_{x}=\lambdag_{x}...- aicort
- Thread
- Lagrange multipliers
- Replies: 5
- Forum: Calculus and Beyond Homework Help
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Volume of a solid limited by two paraboloids
yeah i know... i realized too late :P i hope someone move this thread to that section look this is what i did http://img413.imageshack.us/img413/2806/volt.th.jpg- aicort
- Post #4
- Forum: Precalculus Mathematics Homework Help
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Volume of a solid limited by two paraboloids
Volume of a solid limited by these two paraboloids z=2x^2{}+y^2{} and z=12-x^2{}-2y^2{} hi can someone help me? I tried to solve this and my solution was \ 24\Pi is it correct? can someone solve this step by step?- aicort
- Thread
- Solid Volume
- Replies: 5
- Forum: Precalculus Mathematics Homework Help