Recent content by ajeet mishra

Because most of the times it is easier to solve Schrodinger equation in position basis. As we know Hamiltonian H is given by H= p2/2m + V(x) Now when V(x) is simple function of x ( like harmonic oscillator ) then both position and momentum basis can be used to solve the problem with almost...

But how? As there are unique solutions for drichlet and neumann conditions separately and these, in general, may not be consistent.

My professor told that poission equation has a unique solution even for mixed boundary conditions( i.e. Dirichlet bc for some part and Neumann for the remaining part). But how is this possible? As different boundary conditions for the same problem will give different solutions.

Then there has to be a point of either maximum or minimum potential. At that point, ## \nabla ^2 V ## is not zero and has to be equal to ## \rho / \epsilon _0 ##. But it is not possible since there is no charge inside. Hence the potential has to be constant. The electric field, ## E = - \nabla...

yes we can! And if I apply Gauss law I get zero electric flux(as q enclosed=0) but electric flux =0 does not necessarily imply E=0

it's a hollow cubical box

I have read that electric field at any point( not only at center) inside a uniformly charged spherical shell is zero(by symmetry). But if we take a uniformly charged cubical box, will electric field be zero at every point inside the box? I am confused please help ( I think it should not be zero...

thanks I have got it

Hi! I am having problem in understanding the difference between phase and group velocity clearly. In my textbook phase velocity is given by ω/κ while group velocity is by dω/dκ. What is the difference between these two terms? Thank you!

I became very happy when I saw this site first time where you can discuss any problem of physics.