Recent content by Alec

Homework Statement I'm writing a report about the gravitational constant G. I have trouble figuering out what all the variables mean means. G = w^2 * r^2 * d(Φ1 - Φ2) / 2M(1 + d/r(Φ1 - Φ2)) The experiment was executed in Cavendish torsion balance. Two wires which held 2 large orbs, and 2 small...

Homework Statement Decide the real value of x making Re(10 / x+4i) = 1 Homework Equations I know that you can extend the equation with x-4i. The Attempt at a Solution But then the equation looks like this: (10x-40i) / (x^2 + 16) = 1 I don't know how to get rid of the -40i to make...

yes, sorry. I wrote: Ek = (0.1^2 * V(1)^2) / 0.2 + (0.4^2 * V(2)^2 / 0.8) = 0.0125. Momentum = V1 * 0.1 + V2 * 0.4 = 0.0125. This was before the collision. After the collision it's the same but V(2) = 0 and V(1) = 0.5. So: Ek = (0.1^2 * 0.5^2) / 0.2 + (0.4^2 * 0^2 / 0.8) = 0.0125...

Well I've tried figuring it out but I have no idea how to solve for two unknown s. Physics is really not my cup of tea.

Sorry, yeah my book says Energy is Wk, although Ek is much more logical in English (I'm european if that explains it).

Ok, how? I seriously have no idea. Could it be that Wk = p^2/2m ?

The momentum: P before = P after. But still, I have V1 and V2 unknown.

Hi, two wagons with elastic bumpers colide without any friction. Wagon A has the mass 0.1 kg while wagon B has 0.4 kg. After the collision wagon A has the speed 0.5 meters / second and wagon B lies still. Taken in consideration that the collision was elastic, what velocity does each wagon have...

Alright, my bad :rolleyes: I missed that it's (kx * x)/2 Now, another question. The function for F = kx. The primitiv function for kx = (kx^2)/2 right? Because then you could calculate it as an integral?

Hello, I'm having some problems with the spring constant "k" together with Hookes law. U=1\2kx^2 Could someone please explain how you get that integral? If you insert it in a diagram and calculate the area as a triangle you would get 1/2kx. Where does the ^2 come from?

Well, what are your options? To die instead of giving it a try? Or seize the opportunity given to you? Children starving in Africa is indeed a terrible problem, but look it from this point of view - They don't have the opportunity to do something, you do, but if you don't - you'll realize...

Okay, to put this formula into situations depending on the height above the water level in meters: (x+e)^2 - (x) = "the distance to the horizon" ^2 When I keep my eyes just above the water: (6378150+0.02)^2 - (6378150)^2 = 255126. I can then theoretically see 505.1 meters until I can only...

I'm sorry I was posting for a friend who had troubles registering at this forum. He posted a reply with a picture that clarifies the setting.(above) I just translated this from our mother tongue, thus the bad english and the obscure statement.

"The lower part of a 2.0 meters high road sign is at a distance of 4.0 meters from the car drivers eyes. It's difficult to read the sign at such a distance, as well as when the distance is too short. Investigate how the angle varies when the car is approaching on a straight road. At what...

My problem is to determine how far one can see to the horizon, depending on how far above the water the person is and to create a formula that determines the distance as a function of the height. To start with, the hypotenuse is the distance from the core to the persons eyes. (x+e). The...