Hookes Law and Spring Constant: Explaining the Integral

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Alec
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Hello, I'm having some problems with the spring constant "k" together with Hookes law. U=1\2kx^2

Could someone please explain how you get that integral?
If you insert it in a diagram and calculate the area as a triangle you would get 1/2kx. Where does the ^2 come from?
 
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Alright, my bad :rolleyes: I missed that it's (kx * x)/2
Now, another question.
The function for F = kx.
The primitiv function for kx = (kx^2)/2 right? Because then you could calculate it as an integral?