Recent content by aleee

figured it out, comment if curious.

i got to to write a program for steffensens method on matlab. my equation is x=cosx and my initial value is x0=2 and got to do up to the 14 iterations. error = x_n - a a= 0.7390851332151607 i don't get an answer close to it. i get something around 10.xxxx here is my code. function...

Thanks for the code. I got a few questions to it, but i want to first complete it for i can learn a little programming of it.

This is the project. I have until next week. The requirement for the class is c++. (elementary numerical analysis btw). I have an idea of what is going to happen for the results but i have no idea on how to program it. I've have probably used Matlab 3 or 4 times using a premade program. Can...

oh so for (a) i got it mixed up with the basis for the row space the correct answer is { <1,1,1,0>, < -2,-1,0,1>}

Homework Statement Find (a) a basis for and (b) the dimension of the solution space of the homogeneous system of equations. x - 2y + z = 0 y - z + w = 0 x - y + w = 0 Homework Equations The Attempt at a Solution (a) [1 -2 1 0] => [1 0 -1 2] [0 1 -1 1] => [0 1...

oh sorry my mistake. i ended up doing a while loop then a for loop inside, but thank you for the help

im not sure on how to go about changing it. any advice?

any certain direction i should go in?

i need help making a program that only displays the prime factors ex: 100 = 2*2*5*5 i got the program to display all the factors but after that I am lost. here is the code so far oh its in C++ #include <iostream> using namespace std; int main() { cout << "Enter a number: "...

oh alright, i think i got it. det(A) = det(B)det(T)^-1det(T) det(A) = det(B) thanks for the help!

oh would be it det(A) = det(T^-1)det(BT)?

Homework Statement if T is an invertible matrix, and A=(T^-1)B*T, prove that det B = det A Homework Equations A(BC) = (AB)C The Attempt at a Solution im not certain if inverse T and T will cancel to 1 A=B det A = det B

thanks for the help!

so would i get \int_1^0\\(3t-1)dt and would i just integrate it like that i wouldn't require a negative because its a parametric correct?