Recent content by Alethia

So I'm doing my homework and I get stuck (again) on this problem: Okay what I first did was gather all my given information. That includes all the given dimensions of the pool and dv/dt to be the 1/4 cubic feet per minute. I just need guidance through this problem or where to start... so if...

HAha yeah it would be easier that way wouldn't it? Okay here's my work, that way I can pin point wher eI made a mistake, apparently. :D 1) y = sin x1/2 + sin x1/2 y' = (cos x1/2)(1/2x-1/2) + (cos x1/2)(1/2x-1/2) y' = (2cosx1/2)/(2x1/2 ) y' = cos x1/2 /x1/2 For the second...

Well I was doing my calculus homework today and I got stuck one some problems. Well actually I just wanted to check if I did them right because I'm not entirely sure. Anybody care to check? :D 1) y = sin (9[x^(1/2)] + sin [x^(1/2)] --For this problem, I just used the chain rule for each...

Thank you everyone! I think I just factored wrong on the first one. I used synthetic, but I kept getting the wrong answer, but I get it now. :D

YEah, I typed the problem wrong, but I edited it. And yes I did plug in, and got 0/0 so now that means I need to factor further, so... heh.

Well I just started to learn limits in my calculus class, and I'm getting it fairly well, but I'm a bit confused on these three: 1) the limit of (x^5 - 32)/(x-2) as x approaches 2. The problem I have here is factoring the (x^5 - 32) part. Once I can get that factored I think I can handle...

See that's why I am confused. I've checked my work about a million times (maybe 5 or so times :D) and I keep coming up with the same solution. I checked the answer in the book and it says that the proof is true... so either I'm doing something wrong or it's an error in the book. :1

Yeah that is what I got, but it's not eqaul to the left side, which is what I am supposed to do.

Yes it is me again. :D Now with a trig problem XD I was doing some problems on my homework in math, Trigonometry and I had problems proving this proof: 1+ cos Ө = csc Ө + cot Ө I've worked it out until I simplified the right side to: sin Ө ----- 1+ cos Ө And then I realized...

Yeah I get it now, I think I was just over analyxing it instead of taking it as it was. Thanks everyone! Much appreciated.

But if the direction of the displacement is arbitrary, dependent upon which coordinate system one uses, isn't the answer arbitrary as well? For example, what if someone else chose a different coordinate system than I did in the previous example problem? Wouldn't the final solutions (the force)...

LOL when I said "Right" I did mean "is this right?" Not right as in the direction right (oppposite of left). Sorry O was not clear enough. Sorry but I have another question. XD In this particular problem: x equals a positive 4.3 cm because I am assumign the scale is pushed down, and when...

It depends on the problem then, I am guessing. Hm, let's see... let's say for example, in this problem: . The displacement would then therefore be negative right, because it is pulled away from equilibrium and must travel up (positive direction) to return to equilibrium. Is that right...

I was doing my homeowrk taht dealt with simple harmonic motion and solving problems with Hooke's ewuation (F=-kx). I was a bit confused though on the displacement and when it is negative or positive. For example, when a spring is compressed is the displacement (x) positive or negative? And...

Oh! Thank you! I calculated it and it came out as 50 cm even. =) Thanks!