Recent content by alexdr5398

I've never learned about voltage dividers. Would the Vin in the 2nd stage be larger than the Vout in the 1st stage?

Homework Statement Say you connect Circuit A with low output impedance to circuit B with high input impedance. Why does this cause minimal voltage drop compared to connecting them the other way around (high output to low input). Homework Equations P = V^2/R P = IV The Attempt at a Solution I...

Okay, thank you.

Ah okay, I understand now. So, since path bdce has a lower potential, there will no current going through the third bulb?

I don't really know how to talk about it in terms of electric potential, but when the switch is closed, some of the current that was going through path ae now goes through path af instead. So now bulb B gets a greater share of the current going through bf, so it shines brighter. Is this correct?

Oh I guess I assumed they both shined at the same level initially.

Hey, sorry I haven't answered in a while. So the potential from a to f will be the same as the potential from b to f, right? So if this is the case then why does bulb B shine brighter than bulb A if both paths have the same potential shared between two bulbs?

If lightbulbs A and B have the same resistance, wouldn't the potential across ac be equal to the potential across bd?

Would e, c, d and f have the same potential? And then a and b would also have the same potential?

Okay, I understand. Thank you.

I still don't really understand. So the voltage across A initially would be equal to emf of the source, right? And the voltage across B is a fraction of the emf,with the other fraction shared with the other lightbulb?

Homework Statement Homework Equations μ0 In,e = ∫B⋅ds The Attempt at a Solution I really don't how to approach this question at all. Do you have to integrate counterclockwise around the loop every time? If the field was decreasing as y decreased, would you integrate CW or is it still CCW...

Homework Statement Homework Equations None The Attempt at a Solution The answer is B, bulb B will be brighter than before. My thought was that initially, the current gets split so that 2/3 I0 goes to the branch with 2 bulbs, since it has twice the resistance of the first branch, and that...

Oh, alright. thank you.

Oh I see. So the maximum y value is the amplitude, and that occurs then the sin term is 1. I know what "μ" is, but isn't the amplitude usually measured in metres? Why is the unit "μV/m" in this case?