Why does having a high input impedance and low output impeda

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Homework Help Overview

The discussion revolves around the behavior of circuits with differing input and output impedances, specifically focusing on the effects of connecting a circuit with low output impedance to one with high input impedance, and vice versa. Participants are exploring the implications of these configurations on voltage drop and power transfer.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants are attempting to understand why connecting a low output impedance circuit to a high input impedance circuit results in minimal voltage drop. Questions are raised about the relationship between power, resistance, and voltage drop, as well as the concept of impedance matching.

Discussion Status

There is an ongoing exploration of the concepts of voltage dividers and the implications of output and input impedance on voltage levels. Some participants are providing guidance on relevant concepts, while others are seeking clarification on their understanding of these electrical principles.

Contextual Notes

Participants mention the need for a better understanding of voltage dividers and the distinction between maximum power transfer and minimizing voltage loss, indicating a potential gap in foundational knowledge that may affect the discussion.

alexdr5398
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Homework Statement


Say you connect Circuit A with low output impedance to circuit B with high input impedance. Why does this cause minimal voltage drop compared to connecting them the other way around (high output to low input).

Homework Equations


P = V^2/R
P = IV

The Attempt at a Solution


I am guessing that the power must stay the same when going from circuit A to circuit B, so when the resistance increases, the voltage drops to keep the power equal. But why does this cause a "minimal" voltage drop. Wouldn't matching the impedance be the best way reduce the voltage drop?
 
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alexdr5398 said:

Homework Statement


Say you connect Circuit A with low output impedance to circuit B with high input impedance. Why does this cause minimal voltage drop compared to connecting them the other way around (high output to low input).

Homework Equations


P = V^2/R
P = IV

The Attempt at a Solution


I am guessing that the power must stay the same when going from circuit A to circuit B, so when the resistance increases, the voltage drops to keep the power equal. But why does this cause a "minimal" voltage drop. Wouldn't matching the impedance be the best way reduce the voltage drop?
Think about Vin and Vout. When the output resistance of a stage is high into a low-input impedance stage, what happens to the Vin seen by the 2nd stage? Think voltage dividers... :smile:
 
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berkeman said:
Think about Vin and Vout. When the output resistance of a stage is high into a low-input impedance stage, what happens to the Vin seen by the 2nd stage? Think voltage dividers... :smile:

I've never learned about voltage dividers. Would the Vin in the 2nd stage be larger than the Vout in the 1st stage?
 
alexdr5398 said:

Homework Equations


P = V^2/R
P = IV

The Attempt at a Solution


I am guessing that the power must stay the same when going from circuit A to circuit B, so when the resistance increases, the voltage drops to keep the power equal. But why does this cause a "minimal" voltage drop. Wouldn't matching the impedance be the best way reduce the voltage drop?

I think you are confusing maximum power transfer and minimum signal (voltage) loss.
 
alexdr5398 said:
I've never learned about voltage dividers. Would the Vin in the 2nd stage be larger than the Vout in the 1st stage?
No, Google voltage divder circuits and do a little readng. You'll find that the Voltage Divider equaton is like this:

V_{out} = V_{in} \frac{R_d}{R_i + R_d}

Try that search, and try answering again. :smile:
 

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