Recent content by Ali0086

That would represent the horizontal component of the velocity at max height

alright, first off thanks for not just spoon feeding me answers. I haven't thought through physics like this in a while. So being as literal as I can. 0= vi2- 2gΔd, looking at this equation, the first thing I can think of what that zero represents is the value of vf. So i assume it follows...

well, I know vf2 - vi2 = -2gΔd represents the motion from height zero to the max height. 0= vi2- 2gΔd, so I believe the 0 here would be representing the fact that the vi and 2gΔd are equal right?

the equation 1/2*(final velocity - initial velocity) since 0= vi2- 2gΔd is the initial velocity then isolate for the final velocity?

No it's an object in projectile motion. But what I'm getting at is that if the object is going on a projectile curve, for example a cannonball shot from a cannon. Wouldn't there be a moment in that parabolic motion where the velocity of the vertical component go from positive to negative...

Wouldn't that mean the horizontal component would remain constant, more specifically, the velocity of the horizontal motion wouldn't change.

oh, let me guess, the final velocity will be zero right? The reason being there's that moment where it's absolutely still in the air.

Homework Statement The speed of a projectile when it reaches its maximum height is one-half its speed when it is at half its maximum height. What is the initial projection angle of the projectile? 2. The attempt at a solution First I tried to find the speed for the max height. vf2 - vi2 =...

Alright, so i got these two equations now, am I on the right track or did I go wrong somewhere? ΣFx = m*a = mgSinθ - T Σtorque = I*α = ½Mr^2*α= ½Mr^2*(a/r)edit: Nvm I got the correct answer I used ΣFx = m*a = mgSinθ - T to find my tension and worked on from there Thanks a lot for your help!

So there is no force at all acting on the block? If they give you an acceleration and a mass, wouldn't the product of those two be the force heading down the ramp? That's something that confuses me in FBDs. When is there actually a force present? When one is being constantly applied by an...

An m = 12.4kg mass is attached to a cord that is wrapped around a wheel of radius r = 10.0cm (see the figure below). The acceleration of the mass down the frictionless incline is measured to be a = 2.10m/s^2. a) Assuming the axle of the wheel to be frictionless, and the angle to be θ = 36.2deg...

Thanks a lot! It seems to be a bit more clear now.

Thanks for the well thought out explanation. Unfortunately, I'm in first year calc for university so I don't think I can follow due to no knowledge of partial diff.equations. Anyway to dumb it down so I could understand even better? The other two explanations have helped a bit so I guess I have...

I'm having a tough time understanding uncertainties and the concept of how to find the absolute and relative uncertainties of functions. I understand how to find the relative and absolute uncertainties in problems like 40±2 m (The absolute uncertainty is 2m and the relative is 0.05 if I'm not...