Don't know if anyone else was looking for this data, but after sifting through hundreds of web pages, I think I've got some, just waiting to see if the tutor okays it.
Thanks though to anyone who was helping.
thanks, but i'd tried that. I had actually seen this one before, but the data isn't complex enough for the coursework.
the main problem i am finding is that there is plenty of data about cox regression, but very little about what data sets they used to do the analysis with in the first place.
First of all, I'm not sure if this is the best place to ask this question so if it isn't...sorry.
I'm doing a piece of coursework on cox regression, but I'm having trouble finding any data to use. Most of the data I've seen just gives percentages of people in certain groups, which isn't...
okay, I've had a go at this and i end up with
2pi\frac{(16-r^2)^2}{4}=32pi between the limits of a and 0, where a is the number I'm trying to find. then i'd go on to substitue a in and solve.
could someone tell me if this is right, or have i gone drastically wrong somewhere.
There isn't an order specified, but I would also assume that z would be the outer integral.
Am i right in saying that the largest value for z would be 3, so the z limits are 0 to 3?
okay, I'm not as bad at this as all the questions make me out to be lol
here's the question I've got...
Find the volume bound by 2x+z=3 and y+3z=9 in the positive octant, i.e. x, y and z >=0
what i tried was finding the limits on y first. i got from 0 to 9-3z
for x : 0 to...
the final integral looks simple enough, but believe it or not...i just can't seem to do it. the more i look at it the more i can't do it.
2\pi\int_0^a\sqrt{16-r^2}rdr
could i get a hint as to how to do this? I'm guessing integration by parts, but i can't figure out how to integrate...
i thought it should be 32pi, but you'd got 32/pi further up in the question, so i was just checking.
and asking where the 16-r^2 part came from was a stupid question that i realized the answer to as soon as i clicked on submit reply lol
thanks for the help
shouldn't that be setting it equal to 32/pi not 32pi?
also where does the equation \sqrt{16- r^2} come from?
is this possible to do in cartesian coords? or is this way just easier.
I've proved the volume of a sphere using multiple integration but now i need to use that for the following:
find a so that the volume inside the hemisphere z=sqrt(16-x^2-y^2) and outside the cylinder x^2 + y^2= a^2 is one quarter of the hemisphere.
I'm having trouble even formulating an...
Thats the way I did it at first, but I got a much different answer. I checked my original work and I got a sign the wrong way and the answer turned out to be rubbish. Got it sorted now though. Thanks alot.
This is a question I'm having trouble with.
Solve this equation for a
\iiint \,dz\,dy\,dx = 2/7
I'm new to this code so i'll write the limits here.
the first integral sign is between 0 and 1
the second is between 0 and 4-a-x^2
the third is between 0 and 4-x^2-y
I've got to...