Here is my attempt at answering the above question:
Applying the Principle of Conservation of Linear Momentum:
0 = -(1.10×10^4)×100 + (1.20×10^5)×V
Hence V = 9.167 m/s, where V is the relative speed of the spacecraft after
ejecting the satellite.
I assume that 'phi = 0' means...
A spacecraft (with its cargo, a satellite) is circling the Earth at a
constant speed and an altitude of 600km. The combined mass of the craft and
the satellite is 1.20×10^5 kg (kilograms).
At phi = 0, the captain ejects the 1.10×10^4 kg satellite out the
back. The speed of the satellite...