That's it, I'm putting down what I originally had as my answer:
"Plane's do not drop packages. If this plane dropped the package, then the package would be destroyed."
But, we could assume the package is dropped from an altitude of 900m?
That's what I had thought as well, that the height of the plane was fixed.
If i go with this approach, then the plane doesn't have two velocity components? Only one because the height is unchanging. Which would mean the package's velocity in the y component is due to gravity; it would be in...
I see what you are saying, in the initial velocity it gt is not involved, but AFTER it is dropped, yes.
I think I have worked out a solution.
Bare with me.
1. Vpack (y component) = Vplane*sinθ + gt
2. ((Vpack y)^2 - (Vpack nought y)^2)/(2g) = dy (altitude from which the package has to...
@lewando, the x axis would be the distance's between the nose of the plane and the rear of the ship. The y axis would be the difference in altitudes.
Okay, I drew a diagram
the velocity of the plane is given but it has an x and v component.
Vplane = 180 m/s
Thus the intial velocity...
A plane flies at 900m and has to deliver a package. It flies at 180 m/s North at 15° below the horizontal. The ships velocity is 40 m/s and it is travelling due north. At what horizontal distance from the ship must the package be dropped for it to land on the ship...
I have to derive an equation with the following variables:
and I was told to think of the period as the perimeter of a circle.
The Attempt at a Solution
C=2\pi r,C/2=\pi r,d=\pi r,(at^2)/2=\pi...
The tension (resultant and tension for the hanging box) was calculated using the weight of the hanging box.
Also, I'm in a Trig based physics course and we CAN'T do derivatives, actually we're not supposed to.
I have to find acceleration to calculate how long it takes the heavier box to reach the end of the table.