Deriving the Equation for Period of Simple Pendulum? Is my attempt correct?

AI Thread Summary
The discussion focuses on deriving the equation for the period of a simple pendulum using variables such as period (T), mass (m), angle (Theta), and length (l). The initial approach involves relating the period to the perimeter of a circle and using various equations, including tangential components of force. The importance of considering small angles for simple harmonic motion is emphasized, as it simplifies the derivation of the period. There is a request for clarification or alternative explanations regarding the derivation method. The conversation highlights the need for accurate terminology and understanding in physics problem-solving.
amd123
Messages
110
Reaction score
0

Homework Statement


I have to derive an equation with the following variables:
T= period
m= mass
Theta= angle
l= length

and I was told to think of the period as the perimeter of a circle.

Homework Equations


The Attempt at a Solution


C=2\pi r,C/2=\pi r,d=\pi r,(at^2)/2=\pi r,t=\sqrt{\frac{2\pi r}{Ef/m}},t=\sqrt{\frac{2\pi rm}{sin\Theta r }}
 
Physics news on Phys.org
It is simpler to just draw the pendulum's arc and then use then use the tangential component as the resultant force (F=ma).

This will help you prove that for small angles, the motion is simple harmonic and then the period will be easier to find.
 
I have not come across any of the terminology you have just said.
I doubt I would be allowed to use that method.

Could you describe it in another way or comment on my attempt?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top