Recent content by An1MuS

Ahhh got it ! thank you very much

The diameter of the shaft is 20 mm, and the circumferencial speed is 1,5 m/s, which i calculated doing velocity = angular speed * shaft radius The shaft rotates at 1370 rpm. The graph should give the permissible speeds for the shaft to rotate at that allow the use of the simmerring made of...

Hi, When we have \frac{\partial}{\partial r}(r\frac{\partial p}{\partial r})=0 and we get r\frac{\partial p}{\partial r}=c_1 To get there, did we do this \int\frac{\partial}{\partial r}(r\frac{\partial p}{\partial r}) dr=\int 0 dr or \partial (r\frac{\partial p}{\partial r})=0\partial r...

I did and i won't get any of use for this case, but thanks for the suggestion. :)

I'm working on a group project where we test a bicycle frame on ABAQUS. The test is as follow Where F is a static load. It was suggested for us to consider it as 4G*120kg to simulate a laboratory test. We're having a hard time knowing what is the maximum deflection (or stifness) we should...

Ty :)

I have had this question on my mind for a long time When we solve a differential equation like this \frac{dT}{dx}=0 Do we do this ? \int\frac{dT}{dx}dx=\int0dx\int dT=\int0dxT =c_1 Because if we were to separate variables this doesn't work, we're just integrating both sides in respect...

Y, you're right. So it should be ##F=mkv^2## so that it gives ##kv^2 = \frac {dv}{dt}## Integrating in respect to x, is this it? ##\int kv^2 dx = \int v\frac{dv}{dx}dx## And if it's this i don't know how to continue Also i don't understand this substitution ##\frac{dv}{dt}=v\frac{dv}{dx}##

"m" should already be inside k. ##kt=\frac {-1}{v_f}- (-\frac {1}{v_i})## where ##v_i=1## But then where do the 10meters come in? And what about ##v_f##?

In the fluid problem it's negative, but for the sake of learning, i put it positive to be simpler. Then it's just a matter of me putting a minus sign in the fluid exercise where it's needed. I made up this exercise avoiding fluid mechanics jargon so that more people could understand (and reply...

The whole problem as given is actually a fluid mechanics problem where a ball is dropped and the drag force increases with speed squared. I just stated this one, because if i know how to solve this simpler case i should know how to solve the fluid mechanics one. You guys are right, I updated...

Homework Statement A ball is being pulled by a force given by ##F=kv^2##. Where "k" already includes the mass of the ball. After 10m it will run into a wall. The initial speed is 1m/s and there are no other forces involved. How much time does it take for the ball to hit the wall? Homework...

Hi there, does anyone know a software or program that i can use to quickly sketch / draw and write as if i was writing in pencil ? For instance, paint is of no use, because it can't be edited. Photoshop is kind of hard to simply make straight or curvy lines without too much trouble. So...

Ok i think I've come to grips to what's causing the confusion. Since i saw the magnet flux from north to south, i assumed wrongly that South is where the flux vector always points. But it seems it only points in the direction of the flux on that specific location. So both images are...

Could it be because on the outside the flux of the rotor points upward ? http://imageshack.us/f/14/asdadfq.jpg/