Recent content by andkand97

Oh, okay that makes more sense. Thanks!

Well, the question says "consider pure water separated from an aqueous solution by a semipermeable membrane". Isn't the water being separated from the starch solution?

Consider pure water separated from an aqueous starch solution by a semipermeable membrane, which allows water to pass freely but not starch. After some time has elapsed, the concentration of starch solution a. will have increased b. will have decreased c. will not have changed d. might have...

So I keep getting this problem wrong and I don't know what's wrong. The structure I came up with is attached. If anyone can help I'd really appreciate it!

Oh I understand now. I got a total mass of 22 kg. Is this correct?

Do you mean something like this? (But lighter at the bottom than the top)

Could you explain a little more, please?

Oh sorry. I am told that the candle will fall and hit the table.I'm given a drawing of a candle but nothing else. I know that the mass per unit length increases from 1kg/m at the bottom to 10kg/m at the top. I need to find the impact speed of the candle's flame once the candle hits the...

Homework Statement I need to find the final impact speed of the flame of a non-uniform candle. I am given that the mass per unit length increases linearly from top to bottom starting with 1kg/m at the bottom and 10kg/m at the top. I need to find how fast the candle flame is moving once the...

Oh okay. I finally got the right answer! Thank you so much I've been working on this since yesterday. Really appreciate it!

How would I find the speed of a transverse wave?

Oh...crap. So I subtract the natural length of 3 m from that then use it to find the tension, right?

Well I have the spring constant and I have the distance it is stretched (8.2 m) so I do 18N/m = F/8.2m and solve for F. Is this not right? Or am I supposed to use the natural length instead?

Oh sorry. It's supposed to say the final length is 8.2 meters. As in the slinky is stretched to 8.2 m. Sorry about that.