Recent content by andorrak

Yea i figured that. Thanks so much Dick and Dynamicsolo! Don't worry ill be back. lol

Is it something as simple as multiplying by -1? if so, i feel stupid. but thanks on the absolute values, that would have been a face palm if i hadn't known that on the test day.

Okay so i just used (2, 1, 0) final equation -x+y+z=-1 but the book is saying x-y-z=f I guess they just wanted the normal but why -y-z?

I thought that there were supposed to be absolute values in the equation. If there are not, the way i would calculate it would be then: -i + j + k

This is what i did. |i j k | |1 1 0| |1 2 -1| = *simplified* |-1-0|i-|-1-0|j+|2-1|k which gives me i - j +k

Homework Statement Find a plane perpendicular to the two planes, X+Y=3 and X+2y-z=4 I know i take the cross product of both so i get <1,1,0> and <1,2,-1> But when i do the cross product i get x-y+z book tells me x-y-z what am i doing wrong? Not sure why the z is negative. The...

I believe I got it it is 2 pentane-4-ol. If anyone would like to confirm that it would be great.

no one wants to respond :(

Homework Statement I get that the Br will attach to the triple bond creating a double bond and a Br at the end. I get the gringard reagent but what will the acetone do?Homework Equations The Attempt at a Solution

yea that was a mistype. But why can't the velocities always be positive? I seem to feel like the wave is always moving in one direction unless it's reflected back at me.

Hi yall, Im trying to understand waves and I am wondering why the velocities are negative sometimes and or positive. I think that the velocities are negative because of the slope of the wave as it is coming down? I just want to completely understand it and am a little confused. Like...

wait but how do i get the distance underneath the ramp? Like i got the distance from the moment it leaves the ramp to the end but not before.

Just went and talked with my professor and he showed me what i did wrong: I had everything in place correctly EXCEPT i did not cancel out the r's as I had stated before, ie: Left side: 9.8*.4 Right Side: .5v^2+.5*.4*(R^2)*(V^2/R^2) + (9.8)(.1171) My v then becomes 1.99m/s. The...

Of course i know that dude. but remember Omega = V/R? so the rotational energy is .5IW^2. I was simply canceling out R ahead of time. I= .4R^2 and we have (V/R)^2. the R's cancel out So i just get energy.

I use 0.4 m in the beginning of the equation to represent the PE of the initial state before it begins to roll. I know that the rolling energy is .5Iw^2. But i replace I with 2/5r^2 which is the moment of inertia for a sphere. so the .4 here might be the confusion u are talking about. hence I...