Recent content by andorrak
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Perpendicular Plane to Two Given Planes
Yea i figured that. Thanks so much Dick and Dynamicsolo! Don't worry ill be back. lol- andorrak
- Post #12
- Forum: Calculus and Beyond Homework Help
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Perpendicular Plane to Two Given Planes
Is it something as simple as multiplying by -1? if so, i feel stupid. but thanks on the absolute values, that would have been a face palm if i hadn't known that on the test day.- andorrak
- Post #10
- Forum: Calculus and Beyond Homework Help
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Perpendicular Plane to Two Given Planes
Okay so i just used (2, 1, 0) final equation -x+y+z=-1 but the book is saying x-y-z=f I guess they just wanted the normal but why -y-z?- andorrak
- Post #9
- Forum: Calculus and Beyond Homework Help
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Perpendicular Plane to Two Given Planes
I thought that there were supposed to be absolute values in the equation. If there are not, the way i would calculate it would be then: -i + j + k- andorrak
- Post #6
- Forum: Calculus and Beyond Homework Help
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Perpendicular Plane to Two Given Planes
This is what i did. |i j k | |1 1 0| |1 2 -1| = *simplified* |-1-0|i-|-1-0|j+|2-1|k which gives me i - j +k- andorrak
- Post #3
- Forum: Calculus and Beyond Homework Help
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Perpendicular Plane to Two Given Planes
Homework Statement Find a plane perpendicular to the two planes, X+Y=3 and X+2y-z=4 I know i take the cross product of both so i get <1,1,0> and <1,2,-1> But when i do the cross product i get x-y+z book tells me x-y-z what am i doing wrong? Not sure why the z is negative. The...- andorrak
- Thread
- Cross Cross product Planes Product
- Replies: 11
- Forum: Calculus and Beyond Homework Help
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1 methyl ethyne reacted with i(HBr,) ii(Mg(0), THF, acetone)
I believe I got it it is 2 pentane-4-ol. If anyone would like to confirm that it would be great.- andorrak
- Post #3
- Forum: Biology and Chemistry Homework Help
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1 methyl ethyne reacted with i(HBr,) ii(Mg(0), THF, acetone)
no one wants to respond :(- andorrak
- Post #2
- Forum: Biology and Chemistry Homework Help
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1 methyl ethyne reacted with i(HBr,) ii(Mg(0), THF, acetone)
Homework Statement I get that the Br will attach to the triple bond creating a double bond and a Br at the end. I get the gringard reagent but what will the acetone do?Homework Equations The Attempt at a Solution- andorrak
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- Acetone
- Replies: 2
- Forum: Biology and Chemistry Homework Help
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Why can a velocity of a wave be negative?
yea that was a mistype. But why can't the velocities always be positive? I seem to feel like the wave is always moving in one direction unless it's reflected back at me.- andorrak
- Post #4
- Forum: Introductory Physics Homework Help
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Why can a velocity of a wave be negative?
Hi yall, Im trying to understand waves and I am wondering why the velocities are negative sometimes and or positive. I think that the velocities are negative because of the slope of the wave as it is coming down? I just want to completely understand it and am a little confused. Like...- andorrak
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- Negative Velocity Wave
- Replies: 5
- Forum: Introductory Physics Homework Help
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Rotational Motion/Projectile motion of a ball on a circular ramp.
wait but how do i get the distance underneath the ramp? Like i got the distance from the moment it leaves the ramp to the end but not before.- andorrak
- Post #22
- Forum: Introductory Physics Homework Help
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Rotational Motion/Projectile motion of a ball on a circular ramp.
Just went and talked with my professor and he showed me what i did wrong: I had everything in place correctly EXCEPT i did not cancel out the r's as I had stated before, ie: Left side: 9.8*.4 Right Side: .5v^2+.5*.4*(R^2)*(V^2/R^2) + (9.8)(.1171) My v then becomes 1.99m/s. The...- andorrak
- Post #21
- Forum: Introductory Physics Homework Help
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Rotational Motion/Projectile motion of a ball on a circular ramp.
Of course i know that dude. but remember Omega = V/R? so the rotational energy is .5IW^2. I was simply canceling out R ahead of time. I= .4R^2 and we have (V/R)^2. the R's cancel out So i just get energy.- andorrak
- Post #20
- Forum: Introductory Physics Homework Help
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Rotational Motion/Projectile motion of a ball on a circular ramp.
I use 0.4 m in the beginning of the equation to represent the PE of the initial state before it begins to roll. I know that the rolling energy is .5Iw^2. But i replace I with 2/5r^2 which is the moment of inertia for a sphere. so the .4 here might be the confusion u are talking about. hence I...- andorrak
- Post #18
- Forum: Introductory Physics Homework Help