1 methyl ethyne reacted with i(HBr,) ii(Mg(0), THF, acetone)

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SUMMARY

The reaction of 1-methyl ethyne with HBr and Grignard reagent (Mg(0) in THF) followed by acetone results in the formation of 2-pentanol. The bromine atom attaches to the terminal carbon of the alkyne, converting it into a double bond, while the Grignard reagent facilitates the nucleophilic addition to the carbonyl group of acetone. This process ultimately yields 2-pentane-4-ol as the final product, confirming the initial hypothesis presented in the discussion.

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Homework Statement



I get that the Br will attach to the triple bond creating a double bond and a Br at the end. I get the gringard reagent but what will the acetone do?

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The Attempt at a Solution

 
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no one wants to respond :(
 
I believe I got it it is 2 pentane-4-ol. If anyone would like to confirm that it would be great.
 

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