-12+4i1+16=0 loop 1
what do i do with the 4A in this loop do u do source converction? and change it to voltage? then that's 16V 4A*4OHMS
coz VA =-24V AND 2VA=-48V for the dependent source
2 and 4 ohms are added up
-48+6i2=0 and this is loop2
and one thing is Isc=(i1- i2)? if so how...
so what do u do with the current source then
ya VA was sub and loop2 = 2*-24+2i2+4i2=0
-48+6i2=0
i2=8A isn't that it?
and is ISC=(I1-I2)? IM KIND OF CONFUSED
so u mean loop1 as -12+4I1=0 SINCE SHORT CIRCUIT AB IS THERE?
I1=3 BUT IS LOOP 2 RIGHT?
THEN ISC = -5A, Rth = -36/5
somehow i hva a feeling of that's wrong
k i have loop 1 as -12 +4I1+16=0 and I1 =-1A
loop2 as -48+6I2=0 then I2=8A
is this what u mean in the last post and if so Isc= (I1-I2) = -9A
is Rth become -4?
max power would be?
Wow are u a teacher? That was quick so u did a supper mesh and find out Va and Vth is an open circuit ya? and Now how do i find R's resistor Rth is a short circuits right? only way i know is Rth=Vth/Isc any other way to solve other then the one i menotion any hint to start with finding Isc...
CEL can you write out the equation coz i can't get anywhere close to 36V for Vth!
I did node a (Vth-12)/4 -4+ 2Va+Vth/6=0
Vth equals 14 sth and not even -24 or 36 I am really really lost and i spend any hours on this still can't finish part A how do u do part B and C
Max power is = Rth as...
so is Rth = 4+2+4=10?
and Vth =
(Vth-2Va)/4 +Vth -12/4 -4=0
5Vth-4Va=84
what's Va?
12V/4=3A
3+4=7A
7*4=28v=Va?
Sorry I am trying my best to understand it
i get number one now i have I1 as -2.585A ,I2=-3.732A ,I3=-5A
AND V0= (I1-I2)R= 23V AND POWER = 26.45W
But i still don't know question2 where is the 10v u talking about here is and is Vab = Vth?
Help!New to the circuit
Homework Statement
Question 1
Use the Mesh analysis to find v
0 and power absorbed by the 20 resistor in the circuit
Question 2
a) Find the Thevenin equivalent circuit external to the resistor R
b) Find the condition under which maximum power is transferred to R...