Recent content by Anyiam

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    Common ratio when AP and GP terms are in geometric progression

    Well, i eventually did it this way: [Pth term - Qth term] / [Qth term - Rth term] and i got (p-q)/(q-r). and taking the inverse will also give (q-r)/(p-q), which is true! please is this method satisfactory?
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    Common ratio when AP and GP terms are in geometric progression

    i think the next thing is to eliminate the "d" & "a".
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    Common ratio when AP and GP terms are in geometric progression

    Ok! You are right! Because the common ratio must be the ratio between any two consecutive terms say the Pth term[a plus pd] & the Qth term[a plus qd]. But how do i proceed from here?
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    Common ratio when AP and GP terms are in geometric progression

    Oops! That was some silly mistake on my part! The Pth, Qth & Rth term ought to have been: a plus(p-1)d, a plus(q-1)d, and a plus(r-1)d respectively! pls permit me to use "plus" to indicate addition. Going by this, the difference between the Qth & Pth term becomes d(q-p) and...
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    Common ratio when AP and GP terms are in geometric progression

    1. Homework Statement the Pth, Qth & Rth terms of an arithmetic sequence are in geometric progression. Show that the common ratio is (q-r)/(p-q) or (p-q)/(q-r). 2. Homework Equations for an A.P, the Nth term= a (n-1)d for a G.P, the Nth term= ar^(n-1) 3. The Attempt at...
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    Physics Bsc Eng physics, Msc Mech eng, PhD Mech eng.

    Hello, pls i would like have my bsc degree in engineering physics, after which i will go for my msc in mech.eng and phd in mech eng. pls i would like to know how feasible dis is and it's advantages and disadvantages. All comments especially from exprienced persons will greatly appriceated...
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    Force, pressure and acceleration

    well friend the reason is; the thin pin exerts a greater pressure, beacuse of it small base area as compared with the "thick" pin. Hence, it waz able 2 cause a wreckage through wall by ur applied force, which inturn producd d motion! Generally, the pressure created by a certain force "F" is...