Recent content by Anyiam

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    Relationship between A.P & G.P

    Well, i eventually did it this way: [Pth term - Qth term] / [Qth term - Rth term] and i got (p-q)/(q-r). and taking the inverse will also give (q-r)/(p-q), which is true! please is this method satisfactory?
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    Relationship between A.P & G.P

    i think the next thing is to eliminate the "d" & "a".
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    Relationship between A.P & G.P

    Ok! You are right! Because the common ratio must be the ratio between any two consecutive terms say the Pth term[a plus pd] & the Qth term[a plus qd]. But how do i proceed from here?
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    Relationship between A.P & G.P

    Oops! That was some silly mistake on my part! The Pth, Qth & Rth term ought to have been: a plus(p-1)d, a plus(q-1)d, and a plus(r-1)d respectively! pls permit me to use "plus" to indicate addition. Going by this, the difference between the Qth & Pth term becomes d(q-p) and...
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    Relationship between A.P & G.P

    1. Homework Statement the Pth, Qth & Rth terms of an arithmetic sequence are in geometric progression. Show that the common ratio is (q-r)/(p-q) or (p-q)/(q-r). 2. Homework Equations for an A.P, the Nth term= a (n-1)d for a G.P, the Nth term= ar^(n-1) 3. The Attempt at...
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    Physics Bsc Eng physics, Msc Mech eng, PhD Mech eng.

    Hello, pls i would like have my bsc degree in engineering physics, after which i will go for my msc in mech.eng and phd in mech eng. pls i would like to know how feasible dis is and it's advantages and disadvantages. All comments especially from exprienced persons will greatly appriceated...
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    Force, pressure and acceleration

    well friend the reason is; the thin pin exerts a greater pressure, beacuse of it small base area as compared with the "thick" pin. Hence, it waz able 2 cause a wreckage through wall by ur applied force, which inturn producd d motion! Generally, the pressure created by a certain force "F" is...
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