Recent content by arddi2007

Thank you very much for the heads up. I normally wouldn't make that mistake on my notebook but it's sometimes hard to focus when typing it. By the way, I checked with my professor and he confirmed the solution is correct. Thank you all so much!

Homework Statement 0.5 m3 of air is located in a vessel. Their temperature is T1=0oC and the pressure is p=3·105. What work will be done when heating the gas with constant pressure (isobaric process) to T2=100oC? Homework Equations I was unable to find any equation regarding to the...

Thank you, I just needed the confirmation. So, all that is left to do is to substitute and from there we get: Ek = 2/3 p·V The part that I did not get was that Ek is the average KE per molecule, while the total KE of the gas is N·Ek. Thank you both very much!

Homework Statement Find the Kinetic Energy of the ideal gas \overline{Ek}=? if its volume is 10 liters (10-2 m3) and it is under the pressure of p=5·105. Homework Equations p·V = N·k·T (where p-pressure, V-volume, N-number of particles (molecules), k- Boltzmann constant, T-absolute...

Now that I've checked the literature again, it says that the centripetal force of Earth (Fcp=mv^2 / distance) is equal to the force which Earth and Sun pull each other. Now, my question is, is that correct? If it is, why are they equal?

Homework Statement Knowing that the Earth spins around the Sun for 365 days and the distance Earth->Sun is 1.5x10^11 m, what's the mass of the Sun? Homework Equations F=G Me x Ms/distance^2 where Me - Mass of Earth, and Ms - Mass of Sun In some literature, I noticed that for...

Thank you very much, it now seems all so simple! :P b) Ek=mv2\2=m*1000000m2/s2 / 2 = 500 000 m2/s2 Ek1=m1v12\2=...=562500m2/s2*m(mass) Ek2=m1v22\2=...=62500m2/s2*m(mass) Conclusion: Ek>Ek1+Ek2 which means energy cannot be conserved. Is this correct?Thank you very very much for your help...

Totally forgot about momentum. :P I did the same thing, and formed a system of equations using the following: p=m*v=m*1000 m/s p1=m1*v1=m/2 * 1500 m/s p2=m1*v2=m/2 * v2 p=p1+p2 m*1000m/s=m/2*1500m/s + m/2*v2 ... 2000m/s=1500m/s+v2 v2=500m/s Is this any bit correct?

Not any... That's why I said I'm really unsure about that. I'm generally good with physics but this problem has been eating me up. I cannot figure out any other formula to use in this case. Could you please at least show me which formula(s) to use? Thank you very much for all your help!

I think I have got something, but I may be doing it all wrong. So, we have: v=1000 m/s m Ek=(mv2)/2 v1=1500 m/s m1=m/2 Ek1=(m1v12)/2 v2=? m1=m/2 Ek2=(m1v22)/2 This is the part that I have the doubts for: "Ek=Ek1+Ek2" Although it doesn't seem commonsense to me, I'm still going to...

Not sure... We also know that m gets split in two equal pieces but we've got no specific value for it?! I'm probably missing out something really big! :P

Thank you for your reply tiny-tim. I am really unsure which formulas to use, since all I know is what v is equal to. I am unsure how to find the mass of the shells, in order to find the Ek. I have tried to solve this equation for many days, I even took it to physics teachers and they were unable...

Homework Statement The shell of a shotgun, after being fired, with a velocity of v=1000 m/s gets split into two parts with equal masses. One of the two parts continues to move on the same direction as the whole (not separated) shell did, with a velocity of v=1500 m/s. a) Find the velocity...