Find the Mass of Sun if given are T and d?

  • Thread starter Thread starter arddi2007
  • Start date Start date
  • Tags Tags
    Mass Sun
AI Thread Summary
To find the mass of the Sun using the Earth's orbital parameters, the gravitational force between the Earth and the Sun can be equated to the centripetal force required to keep the Earth in its orbit. The relevant formulas include F = G Me x Ms/d^2 for gravitational force and Fcp = mv^2/r for centripetal force. While gravitational force and centripetal acceleration are not the same, they can be related through Newton's second law, where the gravitational force provides the centripetal acceleration for the Earth. Although the Earth's orbit is slightly elliptical, this does not significantly impact the calculations for determining the Sun's mass. Starting with the centripetal acceleration calculation is recommended for further analysis.
arddi2007
Messages
13
Reaction score
0

Homework Statement


Knowing that the Earth spins around the Sun for 365 days and the distance Earth->Sun is 1.5x10^11 m, what's the mass of the Sun?


Homework Equations



F=G Me x Ms/distance^2

where Me - Mass of Earth, and Ms - Mass of Sun

In some literature, I noticed that for similar problems was used the formula for centripetal acceleration, although I'm not sure why:

acp = v^2/r=(2 x PI x r/T)^2 / r

where r - radius of Earth, and T - time for the Earth to spin around Sun (?).




The Attempt at a Solution



You can notice those two formulas. The literature I found this equation in says that F and acp are equal, but it doesn't explain why. If that's the case, then the equation will be a piece of cake. But I need to know why F (pulling force between Earth and Sun) and acp are equal (if that's correct).

THANK YOU FOR ANY HELP AT ALL!
 
Physics news on Phys.org
arddi2007 said:
You can notice those two formulas. The literature I found this equation in says that F and acp are equal, but it doesn't explain why. If that's the case, then the equation will be a piece of cake. But I need to know why F (pulling force between Earth and Sun) and acp are equal (if that's correct).

They are not equal, and for a very good reason: one is a force and the other is an acceleration. They are different things.

However! They can be closely related through Newton's second law if the acceleration in question is the result of the force in question acting upon a given mass. In this case, that mass is the Earth.

You know that gravitational force is holding the Earth in its orbit around he Sun. This force provides the centripetal acceleration of the Earth in its orbit. Can you find an expression for the gravitational acceleration of the Earth by the Sun?
 
Now that I've checked the literature again, it says that the centripetal force of Earth (Fcp=mv^2 / distance) is equal to the force which Earth and Sun pull each other.

Now, my question is, is that correct? If it is, why are they equal?
 
arddi2007 said:
Now that I've checked the literature again, it says that the centripetal force of Earth (Fcp=mv^2 / distance) is equal to the force which Earth and Sun pull each other.

Now, my question is, is that correct? If it is, why are they equal?

That is correct, assuming a circular orbit for the Earth.

In reality, Earth's orbit is not perfectly circular but very slightly elliptical. So there are small variations in the distance between the Earth and Sun over the course of a year that affects the gravitational force between them. The velocity of the Earth in its orbit also varies slightly over the year as it follows the ellipse. But none of this is going to affect what it is you want to do here.

Why not start by calculating a number for the centripetal acceleration?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top