Thanks for the solution, Stephen!
I actually cracked it yesterday by myself. My original logic turned out to be right:
Since all terms in Xn-1 will be multiplied by a in Xn, we know that every term will be multiplied by a each step into infinity. Furthermore, we know that all new terms in X...
Hey guys! I could still use some help.
The logic I've been working on goes like this:
1/(1-a) (x) = x + ax +a2x + ...
1/(1-a) (x + by) = x + by + a2x + aby ...
Which covers some, but not all of the terms created when you solve the problem by hand.
I'm thinking it might be something like...
I think i might have written it wrong. Xn is a function of both Xn-1 AND Yn-1. I've corrected the mistake in my post.
I think it makes it a lot more complicated than a simple infinite series.
This problem came up in a project I'm doing for work, and I don't have a very extensive math background so I don't know how to solve it. I would appreciate any help you guys could give me.
X1 is a constant
Y1 is a constant
Xn = aXn-1 + bYn-1
Yn = cXn-1 + dYn-1
For all n, for some constants...