Recent content by Aristodol

i am unsure about how to rearrange this equation so that I can solve for x an unknown angle. Please help. we have: sin^2 x(tan x)=1356 it is very simple I no but I just can't remember the way to go about solving this problem, especially because of the sin^2

4.12 is indeed the initial vertical velocity I solved for it and he agreed that that was indeed the correct number. Vf=Vo + at---> 0=Voy + -9.8(.42) Voy= 4.12m/s

huh? not exactly sure what u mean by that?

y=4.12(.42) + 1/2 (-9.8)(.42)^2 1.73 + -.86 y=.87m ok?

I have established that t=.42s we no that Vx=Vox=12m/s also Vfy=0m/s ay=-9.8m/s O i see it now Vf=Vo + at---> 0=Voy + -9.8(.42) Voy= 4.12m/s now what's throwing me off is that i have the velocities for x and y and I am given a distance in 5 but that's not the correct distance

Ive been trying to solve this problem for severall days I have been unable to do it. If you could please just show me the way to go about it it would be appreciated. I've tried many of time but i keep getting stuck.

I no that assuming that x is 5 you get a time .42s i believe. but that's not the time we actually need so that is where i got stuck. I sat there for a long time pondering this question.

the time was not given, that why I had trouble with it. All the information above is exactly what it said on the test.

A boy throws a rock horizontally 12 m/s at a pigeon on a fence 5m away. Unfortunatley the rock the missed. By how much did the rock miss? I ve got my kinematic stuff down pat, but I just had no idea how to go about this problem. thanks for any help.