Recent content by Arquon
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Weight after sliding off a ramp
1 was pointing downwards, while 6 upwards. So do you mean that when the ball is at the top, 6 is pointing downwards as well ? Sorry, I'm a little lost right now :biggrin:- Arquon
- Post #16
- Forum: Introductory Physics Homework Help
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Weight after sliding off a ramp
The height difference is 1R, v is sqrt ( 2Rg ), and weight is 3mg, is that right ? :-p- Arquon
- Post #14
- Forum: Introductory Physics Homework Help
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Weight after sliding off a ramp
I'm a little bit confused. Velocity is still sqrt( 6Rg ) at the top then ? Or rather, sqrt ( 4Rg ), because of 2R height ?- Arquon
- Post #12
- Forum: Introductory Physics Homework Help
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Weight after sliding off a ramp
Velocity at the top is zero, because potential energy is at maximum ? In that case, I get the answer mg, right? :rolleyes:- Arquon
- Post #10
- Forum: Introductory Physics Homework Help
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Weight after sliding off a ramp
Ok, I seem to have got correct answer for the bottom, 7mg ! ( I accidently typed 6mg before :P) Trying to get for the top now.- Arquon
- Post #9
- Forum: Introductory Physics Homework Help
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Weight after sliding off a ramp
a = v2 / R ? :-p- Arquon
- Post #7
- Forum: Introductory Physics Homework Help
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Weight after sliding off a ramp
v = sqrt ( 2g * 3R) ? Got from kinetic and potential energy formula.- Arquon
- Post #5
- Forum: Introductory Physics Homework Help
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Weight after sliding off a ramp
My guess is that Weight is different at the top and at the bottom because of different value of acceleration. I have correct answers, but I don't really know how to get the bottom weight. Bottom is 6mg, top is mg. For Work, I did : Work = 2Rmg ( the work of force of gravity). The loop has a...- Arquon
- Post #3
- Forum: Introductory Physics Homework Help
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Weight after sliding off a ramp
Homework Statement A ball with mass of m starts sliding off a ramp with height h = 3R and when it slides off the ball does a "loop" once. ( Just see the picture , it's hard to explain :biggrin:). I have to find the weight of the ball at the bottom and at the top of the circle. h = 3R Homework...- Arquon
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- Energy Force Ramp Sliding Weight
- Replies: 16
- Forum: Introductory Physics Homework Help
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Maximum force so object on top wouldn't start sliding back
Yeah, it's ok. Thank you !- Arquon
- Post #5
- Forum: Introductory Physics Homework Help
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Maximum force so object on top wouldn't start sliding back
I got acceleration 7.5 m / s2. Then : F = Ffr + ma = 6.5 + 9.75 = 16.25 N ( for friction I used friction between box A and ground, and m = 1.3 kg) Is this correct ?- Arquon
- Post #3
- Forum: Introductory Physics Homework Help
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Maximum force so object on top wouldn't start sliding back
Homework Statement Box B is on top of box A. Box A has a mass of 1 kg, B has 0.3 kg. Coefficient of friction between ground and box A is 0.5, between box A and B : 0.75. With what maximum force can I pull box A without box B sliding back ? m1 = 1 kg m2 = 0.3 kg u1 = 0.5 u2 = 0.75 Homework...- Arquon
- Thread
- Force Friction Maximum Newton Sliding
- Replies: 4
- Forum: Introductory Physics Homework Help
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Understanding Forces in Different Scenarios: Two Questions Analyzed
So generally there can be two answers : 0 if the object is far away from Earth, and mg if the object is falling near Earth ?- Arquon
- Post #10
- Forum: Introductory Physics Homework Help
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Understanding Forces in Different Scenarios: Two Questions Analyzed
I tried using a formula, and I am getting that the answer is mg: W = Fg - ma Fg = W + ma ( W is 0) Fg = ma ( a = g in this case) Is this correct ?- Arquon
- Post #8
- Forum: Introductory Physics Homework Help
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Understanding Forces in Different Scenarios: Two Questions Analyzed
It only says that the body became weightless in pole. I guess we can simply imagine that object is falling towards pole.- Arquon
- Post #7
- Forum: Introductory Physics Homework Help