Recent content by Aryamaan Thakur
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Which Site Will Grignard Reagent Attack: Ketone or Alkene?
This is the given reaction:https://www.physicsforums.com/attachments/1559750554233-png.244625/ Where will the reaction take place - at ketone or at alkene? And why?- Aryamaan Thakur
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- Reaction
- Replies: 1
- Forum: Chemistry
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How could I find the total electric field in this question?
You already found the electric field at centre due to semicircular ring. Find the field due to point charge placed at distance 'a'. Check the directions and add them vectorially (basically just equate them:wink:). P.S. You got the right answer.- Aryamaan Thakur
- Post #5
- Forum: Introductory Physics Homework Help
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Electrostatic potential of a circular ring
Not every single person in this world has graduated. Others might have the same query. Right?- Aryamaan Thakur
- Post #14
- Forum: Introductory Physics Homework Help
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Electric potential at the edge of a thin charged circular plate
It was just this...😂 I solved the whole problem and put the wrong limits😂😂😂 Thanks a lot:smile: You cleared my confusion.- Aryamaan Thakur
- Post #3
- Forum: Introductory Physics Homework Help
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Electrostatic potential of a circular ring
Just one hint! Distance between point A and any point on ring is constant (Pythagoras Theorem - hehe). Take an element dq on the ring. You must know the expression of potential due to a point charge. You'll get an integral. ∫ dq = Q :eek: The answer will come in terms of total charge of ring.- Aryamaan Thakur
- Post #11
- Forum: Introductory Physics Homework Help
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Electric potential at the edge of a thin charged circular plate
My question might sound stupid to you but please clear my confusions. I'm taking an circular arc like element on the plate. That arc has a radius of 'r' (AB) and the radius is inclined at an angle 'θ' with OA (∠OAB). The area between arc of radius r and r+dr is dA. dA = 2θr.dr The charge on...- Aryamaan Thakur
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- Charged Circular Edge Electric Electric potential Electrodynamics Electromagnetism Electrostatics Plate Potential
- Replies: 2
- Forum: Introductory Physics Homework Help
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Prove that r(r^2-1)(3r+2) is divisible by 24
Can anyone help me with this divisibility problem. My approach:- 24 = 2*2*2*3 Now, This can be written as (r-1)(r)(r+1)(3r+2) There will be a multiple of 2 and a multiple of 3. But how to prove that there are more multiples of 2. PLEASE REPLY FAST!- Aryamaan Thakur
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- Elementary number theory Number theory
- Replies: 6
- Forum: Precalculus Mathematics Homework Help
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Atomic Mass: Helium-4 Nucleus Contribution
Ohh! I did a mistake I thought 6.64648310224 is the mass of nucleus. Correcting it! Now, Mass of nucleus = mass of atom - mass of electrons And after you find it divide it with the mass of atom. I hope you've verified the data.- Aryamaan Thakur
- Post #6
- Forum: Biology and Chemistry Homework Help
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Undergrad Is it possible to find the limit of (1+1/x)^x as x approaches -infinity?
I think this problem can be solved in this way. Here is what I think:- let x = -1/y then, Lt (1+1/x)x where x→ -∞ => Lt (1 - y)-1/y where y→ 0 Now let -y = 1/p then, Lt (1 - y)-1/y where y→ 0 => Lt (1+1/p)p where p→∞ And this is equal to e.- Aryamaan Thakur
- Post #11
- Forum: Calculus
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Is There a Student-Friendly Branch on this Forum for Mechanics and Mathematics?
Let me introduce myself. I am Aryamaan and I joined this forum just a few minutes ago. I am currently a student of class 10th. When I was scrolling through questions I noticed that I can't understand anything. Is there something for me in this forum like Mechanics and Mathematics? Do you know...- Aryamaan Thakur
- Thread
- Replies: 1
- Forum: New Member Introductions
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Atomic Mass: Helium-4 Nucleus Contribution
Mass of nucleus = 6.64648310224 Mass of electrons = 9.10939310228 * 2 Mass of atom = 9.10939310228 * 2 + 6.64648310224 = 24.8652693068 Fraction of mass = mass of nucleus/mass of atom = 6.64648310224/24.8652693068 = 0.26729986392797124965341901615185 But the only problem is your data. The...- Aryamaan Thakur
- Post #2
- Forum: Biology and Chemistry Homework Help
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Relative motion of two observers
a) both observers are at rest b) second observer is moving with constant velocity w.r.t the first observer c) both observers are moving with constant velocity w.r.t to a distant star d) second observer is accelerating w.r.t first observer1. if both are at rest the object will seem to move with...- Aryamaan Thakur
- Post #10
- Forum: Introductory Physics Homework Help