Recent content by Aryth

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    Show that f Uniform Differentiable implies f' Uniform Continuous

    Ok then, I see what you're doing. I did not notice that the f(x) and the f(y) were also switched. That helped me finish it, thank you very much.
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    Show that f Uniform Differentiable implies f' Uniform Continuous

    In the first slope you put (y-x) and in the next one you put (x-y)... Is that right?
  3. A

    Show that f Uniform Differentiable implies f' Uniform Continuous

    Just continuous I believe... I may have misstated the problem in the title. Apologies.
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    Show that f Uniform Differentiable implies f' Uniform Continuous

    All that I have been given at this point is that if f is differentiabile at a point, then f is continuous at that point. So all I could say that it would make f uniformly continuous... So, I guess if f is uniformly differentiable, then it has a derivative everywhere, and that should make f'...
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    Show that f Uniform Differentiable implies f' Uniform Continuous

    Homework Statement A function f:(a,b)\to R is said to be uniformly differentiable iff f is differentiable on (a,b) and for each \epsilon > 0, there is a \delta > 0 such that 0 < |x - y| < \delta and x,y \in (a,b) imply that \left|\frac{f(x) - f(y)}{x - y}-f'(x)\right| < \epsilon. Prove that...
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    Net Electrostatic Force on particles

    Ah, that makes perfect sense. Thank you very much for the help. I appreciate it.
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    Net Electrostatic Force on particles

    Thanks for the help guys. And I can't believe I missed that little error. So, my \frac Qq is actually -4.0 and not -2.0. Hey LowlyPion, would you be willing to tell me why (b) is the answer it is. I can kinda see it but I can't make it make sense to me. And thanks for the welcome.
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    Net Electrostatic Force on particles

    Homework Statement Four particles form a square. The charges are q_1 = q_4 = Q and q_2 = q_3 = q. (a) What is \frac Qq if the net electrostatic force on particles 1 and 4 is zero? (b) Is there any value of q that makes the net electrostatic force on each of the four particles 0...
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