Hello everyone.
I'm trying to do a homework in digital integrated electronics class and feel like I can finish it only if I had a good set of notes.
I have problems like comparing the input capacitance of a Mosfet to a wire of certain length, getting RC time loss in a wire, power...
Hello;
I'm a electrical engineering senior and was wondering if passing the F.E. exam would help in the job market. Since I know it is usually catered toward Mechanical engineering and is requirement for Civil engineers, I'm not sure if it would actually state anything for an emerging...
agreed. You will get -v2(t) result. Typically diagrams are drawn with arbitrary direction of current. And once you find the value to be negative it simply implies the original direction of arrow is wrong and simply needs to be reversed.
The air particles are ionized which carry out the lightning bold that we see.
Here is a link to forum post that talks more about this:
https://www.physicsforums.com/showthread.php?t=248535
Hello All;
This is a question I found in semiconductors and devices by Kanaan Kano.
Basically, the volume of a bar of Silicon is given at 300 K [1x0.01x0.2 cm]. How would you find the resistance of the bar if it is intrinsic.
Also, what will be the new resistance after doping of 10^15...
out of curiosity; what kind of deceleration is applied form falling on the net for a safe landing. Too much would cause the person to recoil up. too little would cause he/she to hit the ground.
If you have only a few days left, I suggest that you just relax. Re-read the notes as suggested above. Tedious studding before a test makes me feel tired and not feel like taking it. Well, that’s how I work though.
I solved the problem by calculating the amount of downward force one the person; mainly his weight minus the resistance. Then I used that F in the work formula; W=FD. D would be the 25m. I got the W in Jules so I let that W = KE, which is kinetic Energy. so, W = MV^2. and solved for the desired...
Use proportions to get the amount of KJ in 375 ml.
multiply that # by 1000 to get J.
then use the PE formula:
<< complete solution deleted by berkeman >>
You could solve for the h now.