Recent content by ashleyk

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    Applications of the Definite Integral- Volume

    Hi, I am having trouble visualizing this problem, if anyone can help me see it, I know how to do the integral part. A church steeple is 30 feet tall with square cross sections. The square at the base has side 3 feet, the square at the top has side 6 inches, and the sides varies linearly in...
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    Eek Integrals are ruining my life.

    For the 1st one i am not sure where to start... for the second one, i tried using partial fractions but i could not factor it
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    Eek Integrals are ruining my life.

    Hey I have a test soon and need help on two problems, please! first is taking the integral of (e^(x)^1/2)/(x)^(1/2) dx second is taking the integral of 2/(x^2+4x+8) dx thanks for any help!
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    Calculus 2 Help: How to Integrate 2/((x^2)-1)

    Hi, I have calculus 2 in college right now and am drawing a complete blank and need to get my homework done. If I wanted to take the integral of 2/((x^2)-1)...what would I do or where would I start? Thanks!
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    How do I find the area between two curves with one function not always on top?

    answer of 1 I got the answer of one assuming the bottom is y=0...i have to ask my teacher tomorrow for sure if that is suppose to be one of the curves..
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    How do I find the area between two curves with one function not always on top?

    Possible answer? I got an answer of 1? can anyone verify...??
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    How do I find the area between two curves with one function not always on top?

    Find the area of the region bounded by the curves y=x , y=1/(x^2) , and x=2 I know after you sketch it you have to take the intergral of the top function minus the bottom function from the points that they intersect. I am stuck however because one function does not appear to be on top...
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    Related Rates height of cylinder

    A balloon is in the shape of a cylinder with hemispherical ends of the same radius as that of the cylinder. The balloon is being inflated at the rate of 261 (pi) cubic inches per minute. At the instant the radius of the cylinder is 3 inches, the volume of the balloon is 144 (pi) cubic inches...
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    Discovering Limits: Solving for x Approaching Zero from the Left

    I need some help on my take home AP test. We have been taking the limit as the function approaches infinity but this is problem is when the limit approaches zero from the left...so I'm not sure if I can do that same steps. Find the limit. (limit as x approaches zero from the left) (1 +...
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    Finding 'k' for Continuous f(x) at x=2

    Let f(x) be a function defined by: f(x)= { 2x+1 for x (less than or equal to) 2 .5x + k for x (greater than) 2 A) For what value of 'k' will f(x) be continuous at x=2? Justify your answer. B) Using the value of 'k' found in part A, determine whether f(x) is differentiable...
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    Finding Intervals of Concave Downward with f(x) = 12x^(2/3)

    sorry the orginial function is wrong...it is actually f(x)= 12x^(2/3)-4x I still got the derivative of (8-4x^(1/3)/x^(1/3) but I am still having trouble getting through the second derivative...any help would be great...
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    Finding Intervals of Concave Downward with f(x) = 12x^(2/3)

    Help, Concaved downward?? Let f(x) = 12x^(2/3) Find all the intervals on which f(x) is concaved downward. I know I have to take the second derivative to find the inflection point to find the interval. I figured the first derivative to be (8-4x^(1/3)/x^(1/3) I can't seem to get the...
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    Why Does Calculus Make f(x) Discontinuous?

    Given the function f(x) by f(x) = (2x-2)/((x^2)+x-2) A) For what values of 'x' is f(x) discontinuous? B) At each point of discontinuity found in part A, determine whether f(x) has a limit and, if so, give the value of the limit. C) A rational function g(x)= a/(b+x) is such that g(x)=f(x)...
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    AP Calculus: Finding Derivatives, Tangents, and Graph Points

    yes and i got that answer...im just not sure where to go with it now...
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    AP Calculus: Finding Derivatives, Tangents, and Graph Points

    dextercoiby has the correct function...any more help would be great...
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