Calculus 2 Help: How to Integrate 2/((x^2)-1)

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The integral of 2/((x^2)-1) can be solved using partial fractions. First, simplify the expression to 1/(x^2-1), which factors into 1/((x-1)(x+1)). This can be expressed as A/(x-1) + B/(x+1) for constants A and B. To determine A and B, multiply both sides by (x^2-1) and substitute x=1 and x=-1. Finally, integrate the resulting fractions, utilizing the integral of 1/x.

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ashleyk
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Hi, I have calculus 2 in college right now and am drawing a complete blank and need to get my homework done. If I wanted to take the integral of 2/((x^2)-1)...what would I do or where would I start? Thanks!
 
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Use partial fractions.
 
First, that 2 in front shouldn't bother you. Just do the integral without the 2, then multiply by 2.
[tex]\frac{1}{x^2- 1}= \frac{1}{(x-1)(x+1)}[/tex]
and that can be expanded by "partial fractions":
[tex]\frac{1}{x^2-1}= \frac{A}{x-1}+ \frac{B}{x+1}[/tex]
To find A and B, multiply both sides of that by x2-1 then let x= 1 and -1 in turn.

To integrate the resulting fractions, look up the integral of [itex]\frac{1}{x}[/itex].
 

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