Recent content by Asterast

Thank you so much I got it. :smile:

Isn't m2 actually going downwards overall, even though it's moving upwards wrt m3. So direction of acceleration of m2 should be downwards??

Hello So the first starred equation was a typo for me. Actually I didn't know that acceleration for m2 should be a'-a, I have been trying to solve the problem by taking the acceleration a-a'; because m2 will be going down even though it is moving upwards hence I took a-a' can you please explain...

I'm sorry must have been typing mistake. Let me fix it and check the solution I've solved on paper real quick.

And their final accelerations are equated in eq1,eq2 and eq3

Shouldn't it be different because m2 and m3 will be moving wrt to each other because m3>m2 with acceleration a' The system of m3 and m2 will be moving wrt m1 with acceleration a.

How come? lower string has tension T and T on each side so upper string will have 2T. Also check the equations of m2 and m3, their final accelerations are a-a' and a+a'

I assigned a' for the lower string system since motion of the rate of motion of m2 will be equal to m3 their final accelerations will be a'-a and a'+a for m2 and m3 respectively.

Summary:: I have solved the question but I'm getting answers wrong, some reaction equations seems to have trouble. Question: Let m1 = 1 kg, m2 = 2 kg and m3 = 3 kg in figure. Find the accelerations of m1, m2 and m3. The string from the upper pulley to m1 is 20 cm when the system is released...

:) thanks I'll try this in future threads.

Aye! I got it now. Thank you folks :)

Consider me really dumb but how's the force of descent is equal to sum of forces due to tension and gravitation. Sorry I'm new here, don't know how to rotate the image in the post. Thank you for your time. :)

so I took string below point A and Block as a system. Taking mass of string below point A as m and mass of block M. Taking downward direction as X axis. I get Mg+mg-T, Taking T as tension by upward part of string. Now the question says about block descending with acceleration a. so again forces...

Aster here! I am a mechanical engineer from India. I have worked on electric cart and on automation of tool cutting machines in my course. I'm interested in physics and want to contribute to this forum. Thank you.