# Recent content by AtlBraves

1. ### Easy Conversion Question

I know these questions are simple, but for some reason I can not seem to find the right answers. 1. [HRW7 1.P.002.] A "gry" is an old English measure for length, defined as 1/10 of a line, where "line" is another old English measure for length, defined as 1/12 inch. A common measure for...
2. ### Statistics Problem: Sampling Distributions - Somewhat OT

You are on the staff at the Post Office. Your job is to find a process to find the average waiting time for service. How do you collect the data, and once it is collected, what do you do next?
3. ### Work Done by a Spring Force

I don't understand.
4. ### Work Done by a Spring Force

I am having trouble with this part of the problem. I set it up like this: -.5*m*v^2 = -.5*k*d^2 so v = sqrt((k*d^2)/m) = sqrt((220*.14^2)/.25) = 4.15 m/s. What am I doing wrong? A 250 g block is dropped onto a relaxed vertical spring that has a spring constant of k = 2.2 N/cm (Figure 7-42)...
5. ### Work Done by the Gravitational Force

I made that problem much harder than I should have. I understand now. Thanks for the help.
6. ### Work Done by the Gravitational Force

I can not figure out what I am doing wrong for this problem. Right now I have Wt = 60*.3*cos(50) = 12 J. If that is taken away, then it should be a 12 J difference right? In Figure 7-33, a block of ice slides down a frictionless ramp at angle = 50°, while an ice worker pulls up the ramp (via...
7. ### Friction is giving me trouble

To be honest, I don't know. I can barely understand my professor because of his accent, and my book is useless because it is written in a very complex manner with examples that don't have anything to do with the problems given. I have no idea how to do over half of the problems on the homework...
8. ### Friction is giving me trouble

This problem is giving me trouble. The x-component is -12i, but I don't know how to find the y-component. Can anyone tell me what the forces acting on the block are? A 12 N horizontal force F pushes a block weighing 6.0 N against a vertical wall (Figure 6-25). The coefficient of static...
9. ### Friction Problem

Oops. I mistyped. The correct answer is 11 N I'm hoping. Yes I do now see why the normal force is greater than the weight. Thanks for all of the help.
10. ### Friction Problem

So if F_{f} = \mu N, then F_{f} = \mu * (mg+18sin40) = .25 * ((3.5*9.8)+18sin40) = 12 N?
11. ### Friction Problem

I am having trouble with this problem. I found the answer to a to be 14 N, but the online quiz says it is wrong. Fx-f=0. Fcos(theta)-f=0. f=18cos40=14 N. What am I doing wrong? A 3.5 kg block is pushed along a horizontal floor by a force F of magnitude 18 N at an angle = 40° with the...