Recent content by azzarule

Or h=pi*r^3(t)/3 +c

I went like this and then got stuck again, dh/dt = A**r2(t) dh= A*∏*r2(t) dt h = A*∏*r2(t)*t+C then use t=20 and h=19.7 do I solve for A or c, also I can't solve for either of these because I don't know r??

dh = ∏r2(t) dt h = ∏r2(t2/2)

ok so, dh/dt = ∏r(t)2 h(t) = ∫∏r(t)2 dt = ∏r(t)2(∫dt) =∏r(t)2t so now h(t) = ∏r(t)2t +C

got mixed up, wouldnt the height of the water be equivalent to the y value? and r would be equivalent to x? r2 is then rt2 = dh/dt * 1/pi ??

Homework Statement A dish has a shape described by the equation: h=(x^2+y^2)^3/2 At time = 0 it is filled to a height of 20cm with a fluid that evaporates when exposed to air. The evaporation rate is proportional to the exposed surface area (that is decreasing) at any time t. if h(t) is the...

would the correct integration of dh/2√h just be √h then?

1. Water flows out of a cylindrical tank under gravity via a tap, the height h(t) of the water column above the tap satisfies the differential equation in the form dh/dt = -2k√h where k is some positive constant. The water column has a height initially of 25m. The tap is turned on and...