1. PF Contest - Win "Conquering the Physics GRE" book! Click Here to Enter
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Rate of evaporation from a dish fo water

  1. Nov 6, 2012 #1
    1. The problem statement, all variables and given/known data
    A dish has a shape described by the equation:
    At time = 0 it is filled to a height of 20cm with a fluid that evaporates when exposed to air. The evaporation rate is proportional to the exposed surface area (that is decreasing) at any time t.
    if h(t) is the height of the fluid at time t then
    dh/dt is proportional to pir(t)^2, r(t) is the radius at time t. After 20 minutes the height of the fluid was 19.7cm.
    im trying to make a differential equation that governs the height h(t) during the evaporation.

    2. Relevant equations

    3. The attempt at a solution
    initially I have:
    expressed x as a function of h
    with x=(h^3/2-y^2)^1/2
    now I cant get started on forming the equation from this. Maybe volume is needed?
    Last edited by a moderator: Nov 6, 2012
  2. jcsd
  3. Nov 6, 2012 #2


    User Avatar
    Science Advisor
    Homework Helper

    hi azzarule! :smile:

    (try using the X2 button just above the Reply box :wink:)
    forget x :redface:

    use r :wink:
  4. Nov 6, 2012 #3
    got mixed up,
    wouldnt the height of the water be equivalent to the y value? and r would be equivalent to x?

    r2 is then

    rt2 = dh/dt * 1/pi ??
  5. Nov 6, 2012 #4


    User Avatar
    Science Advisor
    Homework Helper

    no, the height is h (= z)

    r is the radius at height h … you needn't bother with x and y :wink:
  6. Nov 6, 2012 #5
    ok so,

    dh/dt = ∏r(t)2

    h(t) = ∫∏r(t)2 dt

    = ∏r(t)2(∫dt)


    so now h(t) = ∏r(t)2t +C
  7. Nov 6, 2012 #6


    User Avatar
    Science Advisor
    Homework Helper

    no, you can't take r2(t) outside the integral !!

    write h as a function of r
  8. Nov 6, 2012 #7
    dh = ∏r2(t) dt

    h = ∏r2(t2/2)
    Last edited: Nov 6, 2012
  9. Nov 6, 2012 #8
    I went like this and then got stuck again,

    dh/dt = A**r2(t)

    dh= A*∏*r2(t) dt

    h = A*∏*r2(t)*t+C

    then use t=20 and h=19.7

    do I solve for A or c, also I cant solve for either of these because I dont know r??
    Last edited: Nov 7, 2012
  10. Nov 6, 2012 #9
    Or h=pi*r^3(t)/3 +c
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Threads - Rate evaporation dish Date
Related rates (prism with a trapezoid base) Dec 11, 2017
Related Rates problem Dec 11, 2017
Instantaneous Rate of Change Dec 8, 2017
Rate of Change Question Dec 4, 2017
Need Help Solving Set of Coupled ODEs Nov 19, 2016