Recent content by b577phaty

For the block Fx=mgsin(theta)-T-Ff=ma Fy=-mgcos(theta)+N=0 For the pully T=Ialpha T=I(a/r) 10*9.8*sin30-.8a-.2*10*9.8*cos30=10a a=2.72 ?

For my equation, I got mgsin(theta)-I(a/r)-umgcos(theta)=ma however this does not give me the correct answer. Any ideas?

A 20 Kg slender rod pivoted at its center has a length of 6 m. A motor applied a torque of 2400 Nm on the rod to turn it from rest. (a) Find the average power by the motor when the rod rotates an angle of 500 rad. _____________________ (b) Find the instantaneous power of the motor at the...

Homework Statement A block of mass m = 10 Kg is attached to a cable that wraps around the pulley. The pulley is pivoted at the center, and the angle of incline is θ = 30°. The radius of the pulley is R = 0.5 m and its moment of inertia is I = 0.4 Kgm2. The block is released from rest and...