Yah sorry about not showing too much work but that would require a ton of typing and I am lazy. Other than that, I think I have solved it. I found that the line integral over x=0 would cancel out. As for y=0, I determined it to be -1/2 so when I add -1/2 to pi/4+1/6. I get pi/4-1/3 which is...
I used wolfram to see where I mesed up and when it gave me the integral it gave the answer pi/4-1/6 which is also incorrect. Also another weird thing is I did the integral again and I got the same thing wolfram did unfortunatley the back of the book disagrees it says the answer is pi/4-1/3...
Homework Statement
Let C be the (positively oriented) boundary of the first quadrant of the unit disk. Use the definition of the line integral to find ∫(xy)dx+(x+y)dy
Homework Equations
x=rcos(x)
y=rsin(x)
dx=-sin(x)
dy=cos(y)
0≤ t ≤ ∏/2
The Attempt at a Solution...
∫Homework Statement
Use the definition to find the line integral of F(x,y) = (y,x) along each of the following paths.
The parabola y = x^2 from (-1,1) to (1,1)
Homework Equations
F(x) = gradientf(x)
∫F(x) dx = f(b) - f(a)
The Attempt at a Solution
I tried (y,x) dot...