Recent content by Bamboozled91

Yah sorry about not showing too much work but that would require a ton of typing and I am lazy. Other than that, I think I have solved it. I found that the line integral over x=0 would cancel out. As for y=0, I determined it to be -1/2 so when I add -1/2 to pi/4+1/6. I get pi/4-1/3 which is...

I used wolfram to see where I mesed up and when it gave me the integral it gave the answer pi/4-1/6 which is also incorrect. Also another weird thing is I did the integral again and I got the same thing wolfram did unfortunatley the back of the book disagrees it says the answer is pi/4-1/3...

BTW I can do this using Greens theorem

Homework Statement Let C be the (positively oriented) boundary of the first quadrant of the unit disk. Use the definition of the line integral to find ∫(xy)dx+(x+y)dy Homework Equations x=rcos(x) y=rsin(x) dx=-sin(x) dy=cos(y) 0≤ t ≤ ∏/2 The Attempt at a Solution...

Lol your right I goofed it thanks man.

I will try that sorry about the late reply

∫Homework Statement Use the definition to find the line integral of F(x,y) = (y,x) along each of the following paths. The parabola y = x^2 from (-1,1) to (1,1) Homework Equations F(x) = gradientf(x) ∫F(x) dx = f(b) - f(a) The Attempt at a Solution I tried (y,x) dot...