Recent content by Bedeirnur

Relevant equations 1) 2) T = \sqrt{ \frac{m}{k} } 3) T = \frac{2 \pi }{ \omega } In some problems about damped oscillatory motion, the requests ask for example "Calculate the amplitude after 20 oscillations" I know that i need to find the period first of all but : Do i find the period...

I actually already said that there is No point in between where the charge may stay in equilibrium. The text itself here is not correct... I just can't understand the meaning of the negative positions that you get, for example, if you put X as the distance between the higher charge and the...

Well if you've got the solution for that we would know :p Well, it can be anything, we don't know prior...We just know it isn't negative, as the friction force can block it, not drag it.

Why should it be -25? Isn't it like this https://fbcdn-sphotos-h-a.akamaihd.net/hphotos-ak-xpf1/v/t34.0-12/10726541_838742206166089_1666516233_n.jpg?oh=83223884bd9c63131013f875e990f880&oe=543720A0&__gda__=1412890032_b43d01452f1154c45db8a98041885387

Well, say that the first 2 are blocked at their position, i have to place a third one, so it doesn't move...

Well, actually, as my physics professor always says, do not put in the numbers, if not when you've arrived to the last formula. So...The box is moving on the x axis, so we know that the sum of forces on the y-axis is 0. We have |Fp| = |N| +|Fy| With fp being the force exerted by gravity on...

Homework Statement Place a third charge q between two charges Q1 = -2Q and Q2= 3Q so they stay in electrostatic equilibrium. Knowing that the distance between Q1 and Q2 is equal L Homework Equations (KQ1Q)/(QQ1)2 = (KQ2Q)/(QQ2)2 3. The Attempt at a Solution Let's start by saying that i know...

But there's something i can't understand. When using the Torque formula Mtot = Iα... I have that Mtot is the sum of the 2 torques, I is the sum of the 2 inertial moments. But i can't understand at all what that α is here...as the two have 2 different angular velocities i can't understand how to...

The total moment of inertia should be I1+I1 --> m*L1^2+m*L2^2= m*(L1^2+L2^2) right? PhantomJay isn't it asking the linear acceleration? because as α = a * L it is different for the 2 blocks? EDIT it's a = α * L so it might be α as it's equal for both

Homework Statement Two blocks of mass m are suspended on the ends of a rigid weightless rod of length L1 + L2; With L1=20 cm and L2= 80 cm. The rod is held horizontally on the fulcrum shown in the diagram and then released. Calculate the accelerations of the two blocks as they start to move...

Ok! problem solved then, understood everything :thumbs: Thanks a lot ehild and everyone that has posted here to help me! You've all been really helpful! Have a good day and see you the next problem, i hope there won't be one really soon haha. :smile:

In this case ehild i just can't understand you, sorry but for my little knowledge i can't arrive to your point. Let me explain what I've understood and someone tell me if that's what was meant. For Newton's third law : "For every action, there is an equal and opposite reaction." Let's...

In facts it'll slide/accelerate. All clear thanks :) What do you mean by saying there is an issue with using g in mgcos37? Isn't that the component in y of the Weight force in the y direction?

Thank you for the answer. First of all i'd like to show you an image so it is clearer. Did you assume they are asking the N normal force by the answer or by what? Because "Total force" doesn't actually mean N or not? Is the problem in how they asked the question? For the rest, I've understood...

:confused:Well, the problem doesn't say the block stays on the plane. I've just assumed so. How can i know if the block detaches from the plane? Maybe that's the problem, the block detaches from the plane, or not? I've thought as the component in y of the weight force is greater than the...